Solve by using the quadratic formula?

Question

x^2 + 2x -24 = 0

Answer 1

ax^2 + bx + c = 0
a = 1, b = 2, c = -24

x = [(-b) +/- (b^2-4ac)^0.5]/2a
x = [(-2) +/- ((-2)^2 - 4*1*(-24))^0.5]/(2*1)
x = [-2 +/- (4+96)^0.5]/2
x = [-2 +/- (100^0.5)]/2
x = [-2 +/- 10]/2
x = [-2 + 10]/2 or x = [-2 - 10]/2
x = 8/2 or x = -12/2
x = 4 or x = -6

Hope this helps =)

Answer 2

x^2 + 2x - 24 = 0

x = (-b ± sqrt(b^2 - 4ac))/(2a)

x = (-2 ± sqrt(2^2 - 4(1)(-24)))/(2(1))
x = (-2 ± sqrt(4 + 96))/2
x = (-2 ± sqrt(100))/2
x = (-2 ± 10)/2
x = (-12/2) or (8/2)
x = -6 or 4

Answer 3

time for you to buy a TI 83+

go to purplemath.com and look up the advance algebra section. That area will help you to solve these types of problem step by step.