You are right, there is little to simplify here, except maybe the division inside the log, which becomes subtraction:
-a{log (a + sqrt(a^2-y^2)) - log y}
When I get a formula like this, I sometimes define b = a/y, so that a = b*y, and the expression becomes
- b y log [b + sqrt(b^2 - 1)]
That's as simple as you'll get it.
2006-08-24 07:08:36
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answer #1
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answered by dutch_prof 4
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The log of a quotient is equal to the difference of the logs
Log (a/b) = Log (a) - Log (b)
You can also shift the coefficient to the exponent of the Log if it helps
a * Log (b) = Log [(b)^a]
2006-08-24 06:37:36
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answer #2
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answered by Duluth06ChE 3
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-a log[(a+sqrt(a^2 - y^2))/y]
=a log[y/(a + sqrt(a^2 - y^2))]
or
log[y/(a + sqrt(a^2 - y^2))]^a
which are all equivalent expressions and not simplifications.
There is no simpler way of writing the expression.
2006-08-24 08:09:57
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answer #3
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answered by bassbredrin 2
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simplify the rooted eqn.
remember PEMDAS.
and remember log of a number is simply the expotential reciprocal.
just wanted to give some reminders.
2006-08-24 06:35:00
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answer #4
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answered by Euphony 2
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I looks like all you can do it move the "/y" outside the log term as
-log(y)
2006-08-24 06:37:31
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answer #5
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answered by Anonymous
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-a * log((a + sqrt(a^2 - y^2))/y)
-a * log(a + sqrt(a^2 - y^2)) - log(y)
as far as i can get
-alog(a + sqrt(a^2 - y^2)) + alog(y)
or
alog(y) - alog(a + sqrt(a^2 - y^2))
2006-08-24 13:43:48
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answer #6
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answered by Sherman81 6
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Quish! Whew!
2006-08-24 07:46:00
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answer #7
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answered by bo dee 1
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98/989765
2006-08-24 07:31:08
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answer #8
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answered by Beans B 1
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you are correct,
it cannot be simplified
2006-08-24 07:24:20
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answer #9
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answered by locuaz 7
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