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-a log[(a+sqrt(a^2-y^2))/y]

I could not simplify it. I have double-checked the placement of parentheses.

2006-08-24 06:32:44 · 9 answers · asked by rgsoni 2 in Science & Mathematics Mathematics

9 answers

You are right, there is little to simplify here, except maybe the division inside the log, which becomes subtraction:

-a{log (a + sqrt(a^2-y^2)) - log y}

When I get a formula like this, I sometimes define b = a/y, so that a = b*y, and the expression becomes

- b y log [b + sqrt(b^2 - 1)]

That's as simple as you'll get it.

2006-08-24 07:08:36 · answer #1 · answered by dutch_prof 4 · 1 0

The log of a quotient is equal to the difference of the logs

Log (a/b) = Log (a) - Log (b)

You can also shift the coefficient to the exponent of the Log if it helps

a * Log (b) = Log [(b)^a]

2006-08-24 06:37:36 · answer #2 · answered by Duluth06ChE 3 · 0 0

-a log[(a+sqrt(a^2 - y^2))/y]

=a log[y/(a + sqrt(a^2 - y^2))]
or
log[y/(a + sqrt(a^2 - y^2))]^a
which are all equivalent expressions and not simplifications.
There is no simpler way of writing the expression.

2006-08-24 08:09:57 · answer #3 · answered by bassbredrin 2 · 1 0

simplify the rooted eqn.
remember PEMDAS.
and remember log of a number is simply the expotential reciprocal.

just wanted to give some reminders.

2006-08-24 06:35:00 · answer #4 · answered by Euphony 2 · 0 1

I looks like all you can do it move the "/y" outside the log term as
-log(y)

2006-08-24 06:37:31 · answer #5 · answered by Anonymous · 1 0

-a * log((a + sqrt(a^2 - y^2))/y)

-a * log(a + sqrt(a^2 - y^2)) - log(y)

as far as i can get

-alog(a + sqrt(a^2 - y^2)) + alog(y)
or
alog(y) - alog(a + sqrt(a^2 - y^2))

2006-08-24 13:43:48 · answer #6 · answered by Sherman81 6 · 1 0

Quish! Whew!

2006-08-24 07:46:00 · answer #7 · answered by bo dee 1 · 0 1

98/989765

2006-08-24 07:31:08 · answer #8 · answered by Beans B 1 · 0 1

you are correct,
it cannot be simplified

2006-08-24 07:24:20 · answer #9 · answered by locuaz 7 · 1 0

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