2006-08-24 03:09:18 · 4 answers · asked by unquenchablethirst 2 in Science & Mathematics ➔ Mathematics
5x^2 -80y^4 = 5(x^2 - 16y^4)
= 5(x - 4y^2)(x + 4y^2)
by factoring out 5 and using the method of difference of two squares
2006-08-24 06:11:31 · answer #1 · answered by MathMaven53 1 · 0⤊ 0⤋
why should i do your homework.. i have enough of my own to deal with.. and you won't learn anything if i do yours.. but i will so here goes
5x squared - 80y to the power of 4 = 5(xsquared-16y to the power of 4)
2006-08-24 03:18:19 · answer #2 · answered by Anonymous · 0⤊ 0⤋
5x^2 - 80y^4
5(x^2 - 16y^4)
5(x - 4y^2)(x + 4y^2)
5(x + 2y)(x - 2y)(x + 4y^2)
to take this further, you would get
5(x + 2y)(x - 2y)(x + 2iy)(x - 2iy)
2006-08-24 03:16:04 · answer #3 · answered by Sherman81 6 · 0⤊ 0⤋
5x^2-80y^4
=5(x^2-16y^4) -----------> a^2-b^2 = (a+b)(a-b)
=5(x+4y)(x-4y)
2006-08-24 03:13:30 · answer #4 · answered by camedamdan 2 · 0⤊ 0⤋