91 /7= 13
91 + 5 = 96
x=96
2006-08-24 03:01:26
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answer #1
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answered by Anonymous
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well you know that the numbers can be 90, 91, 92, 93 , 94, 95, 96, 97, 98, 99 or 100. If a number divides evenily by 7 then you automatically rule it out. Whatever number has a remainder of 5 after being divided by 7 would be the answer.
In other words find the number that divides evenly by 7 and then add 5 to it.
2006-08-24 10:11:57
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answer #2
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answered by K 5
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You know that X - 5 is a multiple of 7.
If 90 < X < 100, then 85 < X-5 < 95
The only multiple of 7 between 85 and 95 is 91 = 7*13, so X - 5 = 91 therefore X = 96.
2006-08-24 14:13:07
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answer #3
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answered by dutch_prof 4
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90 < x < 100
This is shorthand notation for the combined statement 90< x, x<100. Since we know that x%7=5 (that is, the modulus or remainder of x/7 is 5) we can express x as the sum of 5 and the product of 7 and some whole number (n): 7n+5. Since x = 7n+5, we can substitute it for x
90 < 7n + 5 < 100 {remember, this is 90<7n+5, 7n+5<100}
85 < 7n < 95 {Again this is shorthand, we're actually performing the same operation (subtracting 5) to two different equations}
12.1 < n < 13.2 {And here we divide by 7 in both equations}
Since we know that n has to be a whole number; n must equal 13. So we work back to our starting point.
x=7n + 5
x =(7*13) + 5
x = 91 + 5 = 96
2006-08-24 10:14:32
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answer #4
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answered by hogan.enterprises 5
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90 < x < 100
x = 7*y + 5
if y= 13
x = 7 * 13 + 5
X = 96
90 < x=96 < 100
2006-08-24 10:20:39
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answer #5
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answered by sweetie 5
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91 would give you a remainder of 0 (91=7*13). So X would be 5 more, or 96.
2006-08-24 10:03:10
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answer #6
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answered by Kyrix 6
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96
2006-08-24 09:58:02
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answer #7
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answered by Orlando_KIA 2
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96
2006-08-24 10:05:55
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answer #8
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answered by cantwealljga 1
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90/7, remainder is 6
91/7, remainder is 0
92/7, remainder is 1
93/7, remainder is 2
94/7, remainder is 3
95/7, 4
96/7, 5
Answer is 96
2006-08-24 10:20:11
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answer #9
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answered by ideaquest 7
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96
94/7 = 13 R 5
2006-08-24 10:02:04
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answer #10
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answered by mlc24_1980 3
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