what is x when x+1 / 2x - 3 = 3?

Answer 1

x+1/2x-3 = 3
x+1 = 3(2x-3)
x+1=6x-9
1+9=6x-x
10=5x
10/5=x
2=x

Answer 2

Is that 1/2 or x+1 divided by 2x-3

Answer 3

Based on the way you spaced it out, I'm assuming (rightly or wrongly) that you want to divide x+1 by 2x, not add x to 1/2x. In other words, I've put parantheses around x+1 and 2x.

--- (x+1)/(2x) - 3=3
--- (x+1)/(2x) = 6
--- x+1 = 12x
--- 1 = 11x
--- 1/11 = x

Plugging in 1/11 into the original equation to check we have...

--- [(1/11)+1]/2(1/11) - 3 = 3
--- (12/11)/(2/11) - 3 = 3
--- (12/2) - 3 = 3
--- 6 - 3 = 3 (this is obviously true)

Answer 4

x + 1/2x - 3 = 3

2x - 3(x + 1/2x - 3) = 3(2x - 3)

Clearing the fraction multiplying both sides by 2x - 3

x + 1 = 3(2x - 3)

x + 1 = 6x - 9

The distributive property on the right side of the equation

x + 1 = 6x - 9
+ 9 + 9

adding + 9 to both sides of the equation

x + 10 = 6x

-x - x

subtracting - x from both sides

10 = 5x

10/5 = 5x/5

Dividing five (5) from both sides

2 = x

The answer is x = 2

Answer 5

I assume the equation is (x+1)/(2x-3) = 3

Thus x+1 = 3(2x-3)
x+1 = 6x-9
-5x = -10
x =2

Answer 6

x=2

Answer 7

wow I so don't remember how to do polynomials

can't be 2, then that equation wouldn't equal

2 + 1/2(2) - 3 = 3
2 + 1 - 3 =3
3 - 3 = 3

don't think so

the answer is 4

4 + 1/2(4) - 3 = 3
4 + 2 - 3 =3
6 - 3 = 3


You have to remember your order of functions. Mulitply, then divide, then add, then subtract. It's not (X+1) / (2x-3)

Answer 8

x+1\2x-3 = 3 l+3
x+1\2x = 6 l *x
x*x+1\2 = 6x l -6x
x(x-6) +1\2 = 0
(x-3)(x-3) - 9 +1\2 = 0
(x-3)(x-3)= 8.5
x-3=+sqrt8.5
or
x-3=-sqrt8.5
x=-sqrt8.5
or
x=3+sqrt8.5
estimate
x = 5.9154759474226502354370764387728
or
x= 0.084524052577349764562923561227208

Answer 9

(x + 1)/(2x - 3) = 3
x + 1 = 3(2x - 3)
x + 1 = 6x - 9
-5x = -10
x = 2

Answer 10

x + 1 = 3 * ( 2x - 3 )
x + 1 = 6x - 9
5x = 10
x = 2