To clarify, dividing by a negative number is the same as dividing by the same positive number. hence 10/-5=2 10/5=2.
2006-08-23 18:21:52
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answer #1
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answered by Sleeping Troll 5
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Assuming that those are absolute value signs, the inequality is can be simplified to this:
-12x-3/-5<1
Which in turn means that
-6<2x-3<-4 OR 4<2x-3<6
Since a value of x that satisfies either statement will satisfy the entire problem, a good final answer should be that
-1.5
2006-08-23 18:20:26
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answer #2
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answered by Mehoo 3
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||2x - 3| - 5| < 1
same as saying
|2x - 3| - 5 < 1 or |2x - 3| - 5 > -1
|2x - 3| < 6 or |2x - 3| > 4
same as saying
2x - 3 < 6 , 2x - 3 > -6 , 2x - 3 > 4 , or 2x - 3 < -4
2x < 9 , 2x > -3 , 2x > 7 , or 2x < -1
x < (9/2), x > (-3/2), x > (7/2), x < (-1/2)
(-3/2) < x < (9/2)
or
(-1/2) > x > (7/2)
so i guess the true answer is (-3/2) < x < (9/2), since (-1/2) > x > (7/2) is covered under the (-3/2) < x < (9/2)
ANS : (-3/2) < x < (9/2)
2006-08-24 03:03:58
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answer #3
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answered by Sherman81 6
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||2x-3|-5| < 1
0 < |2x-3|-5 < 1 or 0 > |2x-3|-5 > -1
5 < |2x-3| < 6 or 5 > |2x-3| > 4
5 < 2x-3 < 6 or -6 < 2x-3 < -5 or 4 < 2x-3 < 5 or -5 < 2x-3 < -4
8<2x<9 or -3<2x<-2 or 7<2x<8 or -2<2x<-1
7<2x<8 or -3<2x<-1
7/2 < x < 4 or -3/2 < x < -1/2
2006-08-23 19:18:26
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answer #4
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answered by Anonymous
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As it is absolute value :
0 < =(2x-3)-5 <1
adding 5 :
5 < =2x-3<6
as 5 is positive we can remove the absolute value. adding 3 :
8 <2x<9
so
4<=x<4.5
So x between 4 and 4.5
2006-08-23 18:10:37
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answer #5
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answered by fred 055 4
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//2x-3/-5/<1 =>
-12x-3/-5<1 =>
42x-3/<6 =>
+4<2x-3<+6 (case1) and
-6<2x-3< - 4 (case2)
Case 1:
7<2x<9 => 3.5 x is in (3.5 , 4.5)
Case 2:
-3<2x<-1 => -1.5 x is in (-1.5 , -0.5)
=>
x is in (3.5 , 4.5)U(-1.5 , -0.5)
2006-08-24 05:12:56
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answer #6
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answered by d13 666 2
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"int main()
{
int time=0;
if laundry == full
{if time =! 0
{cout <<"buy new clothes"<< endl;
}
else
cout << "don't forget to bring laundry home for thanxgiving" << endl;
}
return;
}"
2006-08-23 18:31:11
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answer #7
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answered by Aki 4
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just a question: what do the slashes("/") mean?
do they mean: "divide"?
2006-08-23 21:50:56
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answer #8
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answered by harley_first 1
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