Homework Help? - Geometry?

Question

I am given that on a segment, BC=2x+32, & AC=12x . How would I figure out what "AB" and "x" are?

this is not a triangle, the points are in a straight line

Answer 1

I agree with g_midori; basically you know the length of the entire line is 12x, and the length of BC is (2x + 32), so:

AB + (2x + 32) = 12x
AB = 10x - 32

One other thing that comes to mind is that you may have been told something like B is midway between A and C. In that case you can solve for AB and x by saying:

2(2x + 32) = 12x

so:
x = 8
AB = 48

Answer 2

if A, B, and C are all connected by a straight line (in that order), then

AB = AC - BC

AB = 12x - (2x + 32)
= 10x - 32


I think some info is missing to find out what x equals, unless you want to express it as

x = AC/12 = (BC - 32) / 2 = (AB + 32) / 10


If this is a triangle, we need more info, like what kind of triangle, and if it's a right triangle, which segments are the hypotenuse, legs, etc.?

Answer 3

Is this a triangle?

Answer 4

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