Because you are the puppetmaster.
Actually, you're like her overprotective, rich father. She's a hottie, so she'd be pretty popular on her own, but you buy people to hang out with her so she's doesn't fall in with a "bad crowd", lots of things to occupy her time (her ice-cream shop), and basically anything to keep her away from boys.
Ken is probably a gay actor you hired to go out with her too.
This whole scheme will not end as you envision -culminating with Barbie's involvement in an incident at the Malibu beach house (concerning Mel Gibson and supercar racing down the 101), and a budding "curiosity" about lesbianism.
2006-08-23 15:12:24
·
answer #1
·
answered by Shofix 4
·
0⤊
0⤋
Because she's just a toy. She cannot be popular because she is not alive. Buying her friends, would be other toys. Oh man..it's 9:45..time for my daily dose of satire pills.
Bye!
2006-08-23 21:47:39
·
answer #2
·
answered by muva2003 3
·
0⤊
0⤋
You know something I was in an adult store the other night and saw a bumper sticker that said that and I cracked up laughing....good point whoever thought it up!!!
2006-08-23 21:46:21
·
answer #3
·
answered by corry692001 2
·
0⤊
0⤋
Easy so barbie can have an orgy.she's gotta have sum fun too.lol.
2006-08-23 21:52:00
·
answer #4
·
answered by ramlover_92 2
·
1⤊
0⤋
I never thought of it that way. Yay and she can't buy her own clothes or car she is a gold digger.
2006-08-23 21:45:11
·
answer #5
·
answered by masterurownmind 5
·
0⤊
0⤋
In this materialistic world, that is the only way to get friends.
2006-08-23 21:48:10
·
answer #6
·
answered by Anonymous
·
0⤊
0⤋
she wouldnt be popular with out her friends
2006-08-23 21:45:01
·
answer #7
·
answered by asd_5_98 2
·
0⤊
0⤋
cause she's a lonely neurotic dysfunctional freak like everybody else...and don't we have to "buy" OUR friends????
2006-08-23 21:47:21
·
answer #8
·
answered by peacetrain 3
·
0⤊
0⤋
Good question.
2006-08-23 21:55:15
·
answer #9
·
answered by . 5
·
0⤊
0⤋
caz her friends want be pop too
2006-08-23 21:46:43
·
answer #10
·
answered by Jubei 7
·
0⤊
0⤋