2006-08-23 12:46:53 · 10 answers · asked by Anonymous in Education & Reference ➔ Homework Help
Maybe I should've been a little more specific, so here goes. x^2-x+12, I wanted to know if it could be factored not solved..
2006-08-25 05:52:40 · update #1
Not the way you wrote it. By itself, there's nothing to solve.
Now, if it's equal to something, then you can solve for x. Assuming x2 means x squared, you can solve for:
x^2-x+12=0.
That's an assumption. Usually, these problems are set equal to 0. If that's not the case, then you need to clarify.
You can't just foil it. WIth the +12, you know that both roots are either positive or negative. You can't get a -x out of that.
You can plug it into the quadratic formula with a=1, b=-1, and c=12.
2006-08-23 12:48:22 · answer #1 · answered by Rev Kev 5 · 0⤊ 0⤋
Yes by using the factoring method.
x^2 - x + 12
(x-4)(x+3) = 0
x = 4, -3
2006-08-23 19:48:29 · answer #2 · answered by Crescent 4 · 0⤊ 0⤋
I assume you mean 0=x^2 - x + 12
No, it cannot be solved with real numbers.
(x-3)(x-4) = x^2 - 7x +12
(x+3)(x+4) = x^2 + 7x + 12
(x-3)(x+4) = x^2 + x -12
(x+3)(x-4) = x^2 - x - 12
2006-08-23 19:56:34 · answer #3 · answered by sassy_91 4 · 0⤊ 0⤋
no. that's only 1/2 of the equation. an equation needs an equal sign.
2006-08-23 19:50:45 · answer #4 · answered by animal_mother 4 · 0⤊ 0⤋
No, it's not a complete equation -- just an expression -- so there's nothing to solve.
2006-08-23 19:51:13 · answer #5 · answered by ConcernedCitizen 7 · 0⤊ 0⤋
you have to right = what?
to have an equation in the first place to solve
2006-08-23 19:50:32 · answer #6 · answered by sea lover 2 · 0⤊ 0⤋
(x + 3)(x - 4)
by using the foil method
2006-08-23 19:49:47 · answer #7 · answered by creative_idea_thinker 2 · 0⤊ 0⤋
Not unless you know the value of X
2006-08-23 19:49:30 · answer #8 · answered by IMHO 6 · 0⤊ 0⤋
........sure x2-x+12 can be solved........
2006-08-23 19:49:56 · answer #9 · answered by Anonymous · 0⤊ 0⤋
that way it cant be
2006-08-23 19:51:21 · answer #10 · answered by xobabieexo10 1 · 0⤊ 0⤋