AB=24, AB=2/3C. AC=?
2006-08-23 12:03:17 · 7 answers · asked by brighton 3 in Science & Mathematics ➔ Mathematics
A----B------C:
ab=24, ab=2/3bc which means 24=2/3bc. So 3/2*24 =bc = 36 and ac = ab+bc = 60
OR
A----B--C
ab=24, ab=2/3ac which means 24=2/3ac. So 3/2*24 = ac = 36. bc=1/3ac = 1/3*36 =12.
2006-08-23 12:07:39 · answer #1 · answered by maegical 4 · 1⤊ 0⤋
because A is between B and C, and the three factors are collinear, the phase addition postulate means that AB + AC = BC. Substituting the given expressions for AB, AC, and BC, we've 4x - 3 + 5x - sixteen = 7x + 5 9x - 19 = 7x + 5 2x = 24 x = 12. BC = 7x+5 = 7(12)+5 = 89; AB = 4x-3 = 4(12)-3 = 40 5; AC = 5x-sixteen = 5(12)-sixteen = 40 4. Lord bless you at present!
2016-12-17 16:06:24 · answer #2 · answered by joyan 4 · 0⤊ 0⤋
We have A----B--------C, we set point A as X=0 on the coordinate system, the the value of C is the distance AC.
AB = 24 = (2/3/)C, multiply both sides by (3/2)
(3/2)*24 = 12*3 = 36
2006-08-23 12:11:11 · answer #3 · answered by Anonymous · 0⤊ 0⤋
36
2006-08-23 12:15:50 · answer #4 · answered by sonicwingmode 2 · 0⤊ 0⤋
36
2006-08-23 12:09:12 · answer #5 · answered by Efrayim 2 · 0⤊ 0⤋
AC = 36 therefore, B is between AC
2006-08-23 12:50:02 · answer #6 · answered by justcurious 1 · 0⤊ 0⤋
mklkljkl
2006-08-23 12:04:59 · answer #7 · answered by Anonymous · 0⤊ 0⤋