2006-08-23 11:39:46 · 9 answers · asked by jadetiger_design 1 in Science & Mathematics ➔ Mathematics
The numbers are 23 and 35.
35 + 23 = 58
35 - 23 = 12
2006-08-23 11:42:22 · answer #1 · answered by FJS 5 · 0⤊ 0⤋
x + y = 58 , x -y = 12
x = 12+y
=> 12+y+y = 58
=> 2y = 46
=> y = 23 ........ => x = 35
2006-08-23 11:49:18 · answer #2 · answered by Ayman 3 · 0⤊ 0⤋
This and comparable issues are hassle-free to artwork out on your head. the two numbers would desire to be extra desirable than and decrease than the mid element of their sum with the help of 0.5 the completed distinction of their values. because 0.5 of 80 = 40 the two numbers would desire to be 40+6 = 40 six and 40 -6 = 34.
2016-12-17 16:05:44 · answer #3 · answered by joyan 4 · 0⤊ 0⤋
30+28= 58 You just subtract a random number from 58, and you get the answer.
2006-08-23 11:45:09 · answer #4 · answered by allison 3 · 0⤊ 2⤋
35 and 23.
35+23=58
35-23=12
2006-08-23 12:50:55 · answer #5 · answered by FauxPas 2 · 0⤊ 0⤋
x + y = 58
x - y = 12
2x = 70
x = 35
x + y = 58
35 + y = 58
y = 23
ANS : 23 and 35
2006-08-23 13:21:12 · answer #6 · answered by Sherman81 6 · 0⤊ 0⤋
we call one x the other is12 more or x+12
x + (x+12) = 58
2x = 46
x = 23
x+12 = 35
2006-08-23 11:46:19 · answer #7 · answered by Gary L 2 · 0⤊ 0⤋
x+y = 58
x-y = 12
2x = 70
x = 35
y = 23
2006-08-23 11:43:13 · answer #8 · answered by Anonymous · 0⤊ 0⤋
23...........35
2006-08-23 12:25:13 · answer #9 · answered by mg_speedy2001 2 · 0⤊ 0⤋