two batsmen at crease r on 94 runs each...their team wants 7 runs to win from 2 balls... How is it possible tht the team wins the game and both the players make their 100... plzz do help!!
2006-08-23 07:54:11 · 17 answers · asked by gaLa 1 in Sports ➔ Cricket
2 players playing on 94 runs each...shud get to their 100runs. their team needs 7 runs to win and there are just 2 balls to go. so how can the two players get to their 100 and make the team win the game
2006-08-23 08:02:47 · update #1
It is Possible only technically, but in real cricket it is like one in a million chance! It would happen in this way
Batsman A is on 94 , Batsman B is on 94 And Batsman A is on Strike.
1. Batsman A hit a shot and ran 3 runs but the fielder over threw. On over throw they ran 3 more runa but the batsman number A got run out at the bowling crease trying to complete a 4th run on over throw.
2. By above he scored 6 runs and got run out so Batsman A got out on 100.
3. Now equation 1 run to win 1 ball left , Batsman B batting on 94 is on strike!
4. Batsman B hit a 6 to win and scored his 100
2006-08-23 10:57:11 · answer #1 · answered by rickashe 4 · 3⤊ 0⤋
Rickashe you are a bloody genius mate
That is the ONLY way it could happen because there are ONLY 2 Balls left (not in the over but the match) and 7 runs needed
Batsman A needs to be run out at the non strikers end going for the 7th. Therefore getting the 6 he needed and leaving
Batsman B at the strikers end to hit his 6 off the last ball of the match. Runs achieved centuries scored.
I just realised there might be another way it could happen using Rickashes scenario but without the batsmen being runout. That is they run 7 or 3 and an over throw goes to the boundary. However the umpire calls1 run short. This leaves batsman B on strike. Only 6 runs are counted ,thus leaving Batsman B to hit a 6 off the last ball and they both are 100 no and win the match.
I might have thought of another way it could happen. Batsman A hits the second last delivery and they run a single. The ball is thrown to the strikers end in an attempted run out but the keeper misses the ball and it hits a fielders helmet placed on the ground behind the keeper. Batsman A is awarded 1 run for the single and 5 runs for it hitting the helmet, thus getting 6 runs and his century. Batsman B is on strike for the last ball and hits it for 6
getting his century and winning the game.
Now this scenario depends on the batsman being awarded the 5 runs and not having it go to sundries. If it goes to sundries then this idea is wrong but someone will correct me if it is.
2006-08-24 01:08:24 · answer #2 · answered by pejon60 4 · 1⤊ 0⤋
it is Possible as cricket is crazy one.one batsman is on 94 , other Batsman is also on 94.. Batsman hit a shot and ran 3 runs but the fielder over threw. On over throw they will take 3 runs the batsman will get his century have 1 ball left ,other Batsman batting on 94 is on strike! Batsman hit a 6 to win and scored his 100 .
hence both get their centuries & team wins.
2006-08-24 08:12:52 · answer #3 · answered by sreenivas k 2 · 0⤊ 0⤋
What I say is only a chance. If it is the last ball of an over, one of them is in the crease. If the ball is hit for a six and it becomes a six, then the team needs 1 run to win. On the starting of the next over the other batsman should hit a six if both of them have to reach centuries.
Hope yur doubt is cleared.
2006-08-23 19:59:13 · answer #4 · answered by chunnu 4 · 0⤊ 1⤋
I would make it simpler. A scores 3, then an over-throw causes them to run for another 4, but alas, could not quite make it, A is out trying the 4th, so he returns making 100, score stands one short of winning target, and B hits last ball for a six.So both make 100 and the team wins---but only theoriticaly.
2006-08-24 00:55:17 · answer #5 · answered by slender 2 · 0⤊ 0⤋
First batsman hits a Six and gets off the mark for the first ball. He has his 100 and the Team needs one.
For the second ball the other batsman hit another one over the top and that brings his hundred and the team wins too.
2006-08-23 23:10:48 · answer #6 · answered by BiCUBIC 2 · 0⤊ 1⤋
Na Na. Its impossible. If even a bowler balls a no-ball and the first batsman hits it for six, the game is over. If the batsman takes five runs even then its not possible because he wont get a century. Its completely impossible.
2006-08-23 17:11:21 · answer #7 · answered by the.chosen.one 3 · 0⤊ 0⤋
at the last ball of the over one should hit a six and on the first ball of very next over another should hit a six and not take a single.that's the only way out but when considering last 2 balls which r of same over this is impossible.
2006-08-26 09:21:00 · answer #8 · answered by rash 2 · 0⤊ 0⤋
1. THE FIRST BALL THE BATSMAN A RUNS 7 RUNS SO HE IS AT THE NON STRIKER END BUT THE UMPIRE CALLS ONESHORT
2. SO NOW THE BATSMAN B IS ON STRIKE HE SCORES A SIX.
BOTH THE BATSMAN SCORES 100!!!!!!!!!!
2006-08-26 10:02:43 · answer #9 · answered by maddy 3 · 0⤊ 0⤋
its damn simple....
first batsman hits a six off the last ball of the over and reaches his 100 and thier team now need 1 run off 1 ball
as the over finishes...other batsman on 94 is on strik and he hits a sixer as welll....whihc will take him to his century!!
simple!!
2006-08-24 00:07:17 · answer #10 · answered by Zuhair-from-pakistan 4 · 0⤊ 1⤋