Jill has $3.50 in nickels and dimes. If she has 50 coins, how many of each type of coin does she have?
Solve by addition
If solution does not exist, state if inconsistent or dependent
2006-08-23 05:25:10 · 7 answers · asked by sistermoon 4 in Education & Reference ➔ Homework Help
One nickel is 0.05 dollars and one dime is 0.10. If n be the number of nickels and d be the number of dimes,
n x 0.05 + d x 0.10 = 3.50 .......(1)
n + d = 50 ........(2)
Multiplying equation (1) by 10, we have
0.5n + d = 35.0 ......(3)
n + d = 50 .....(2)
(2) - (3) gives
0.5n = 15
or n=30
Therefore there are 30 nickels and 20 dimes.
2006-08-23 05:35:26 · answer #1 · answered by Mathew K E 1 · 0⤊ 0⤋
Reducing the problem to cents, we have
5N + 10D = 350 and N + D = 50, if N = nickels number and D = dimes number. (5N since a nickel is five cents, same for dime)
Since N+D=50, if we solve for N we get N=50-D (subtract D from each side. If we then substitute (50-D) for N in the other equation, we get
5(50-D) + 10D = 350
250 - 5D + 10D = 350 (combine Ds and subtract 250)
5D = 100, D= 20
You should be able to do the rest, including going back to both equations to check!
2006-08-23 12:35:12 · answer #2 · answered by Anonymous · 0⤊ 0⤋
You need to solve the following series of equasions.
.10x + .05y = 3.50
x + y = 50
I'll get you started:
x = 50 - y so .10(50 - y) + .05y = 3.50
Now solve for y first.
2006-08-23 12:32:47 · answer #3 · answered by thatgirl 6 · 0⤊ 0⤋
dependently inconsistent
2006-08-23 12:46:31 · answer #4 · answered by choco taco 3 · 0⤊ 3⤋
Shame on you...do your own homework. You need to learn to figure it out for yourself.
2006-08-23 12:34:05 · answer #5 · answered by dkwkbmn 4 · 0⤊ 4⤋
i'm not your math tutor, struggle with the problem and you will benefit from it
2006-08-23 12:31:23 · answer #6 · answered by DodgerBlueFan 4 · 0⤊ 5⤋
DO UR OWN HW WOMEN
2006-08-23 12:44:12 · answer #7 · answered by Rachel 2 · 0⤊ 4⤋