evaluate limx->0 (1-cos4x)/(1-cos5x)?

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evaluate limx->0 (1-cos4x)/(1-cos5x)?

2006-08-23 03:34:13 · 3 answers · asked by manal k 2 in Science & Mathematics ➔ Mathematics

3 answers

You need to apply L'Hopital's rule two times.

Lim x->0 (1-cos 4x)/(1 - cos 5x)

Lim x->0 (4 sin 4x) / (5 sin 5x)

Lim x->0 (16 cos 4x)/(25 cos 5x) which equals 16/25

2006-08-23 03:39:13 · answer #1 · answered by Bob G 6 · 1⤊ 0⤋

Sounds weird

2016-07-27 11:15:20 · answer #2 · answered by Anonymous · 0⤊ 0⤋

This is a good question, and one that has made me curious for a long time.

2016-08-23 05:06:28 · answer #3 · answered by Anonymous · 0⤊ 0⤋