English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

m[to the 7th power] - 2m[to the 6th power] + m[to the 5th power]

2006-08-23 02:21:04 · 3 answers · asked by x0jacqueline223930x 2 in Education & Reference Homework Help

3 answers

m^5 * (m^2 - 2m +1)

m^5 * (m-1) * (m-1)

Note: The key is to pull out as many M as possible at first (hence m^5) and then you are left with a simple polynomial.

2006-08-23 02:24:19 · answer #1 · answered by nicholas_fahrenkopf 2 · 0 0

m^7 - 2m^5 + m^5
(m^5) (m^2 - 2m + 1)
(m^5) (m - 1)^2

2006-08-23 02:25:45 · answer #2 · answered by lemons 3 · 0 0

m(to the 4th)

2006-08-23 02:28:24 · answer #3 · answered by bigbbraz 2 · 0 0

fedest.com, questions and answers