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What were 2 of my last questions today?
Remarkable.

2006-08-22 17:39:23 · 14 answers · asked by ppellet 3 in Science & Mathematics Mathematics

14 answers

For base 2:

1 + 1 = 10

2006-08-22 17:41:14 · answer #1 · answered by Jerry M 3 · 1 0

10

2006-08-23 00:54:22 · answer #2 · answered by Anonymous · 0 0

In base 2 what does 1+1 equal=2^(1+1)=2^2=4

2006-08-23 00:45:13 · answer #3 · answered by Amar Soni 7 · 0 1

if is 10 in base 2 and 2 in base 10

2006-08-23 07:12:56 · answer #4 · answered by Mein Hoon Na 7 · 0 0

Are those values set as a MINIMUM-value slot or MAXIMUM-value slot?
% 00100 (base2)= 4 (base 10)
whereas 01000 (base2)= 8 (base 10)
Count in values of 2 from the right-hand side.
0001 (base2)= 1(base 10)
0010 (base2)= 2(base 10)
0011(base 2)= 3(base 10)
0100(base 2)= 4(base 10)
1000(base 2)= 8(base 10)
etc. etc, etc.
Each increment from the right-to-left of the BINARY digits increases by twice.
I hope this helps and avoids confusion.

2006-08-23 00:54:34 · answer #5 · answered by Anonymous · 0 1

In base 10, 1+1 can be expressed as 0001+0001=0002.
In base 2 that would become: 0001+0001= 0010.
That is because: 0001 1
0010 2
0101 3
1010 4
etc.

2006-08-23 00:46:53 · answer #6 · answered by Dusty 7 · 0 1

In Binary,

1+1 = 10 (base 2)


Counting...

Dec - Bin
0 - 0000
1 - 0001
2 - 0010
3 - 0011
4 - 0100
5 - 0101
6 - 0110
7 - 0111
8 - 1000

2006-08-23 00:59:31 · answer #7 · answered by ideaquest 7 · 1 0

10 but it is pronounced ONE ZERO. Think about this... you have one and you are adding one, but in base 2 system, everytime you reach 2, you increment one place to the left. Hense you get 10.

2006-08-23 00:45:34 · answer #8 · answered by tkquestion 7 · 1 0

1+1 equals two in ANY base. It is just that two is written differently in different bases:

10 is two in base two
2 is two in higher bases.

2006-08-23 05:08:58 · answer #9 · answered by blind_chameleon 5 · 0 0

There are 10 kinds of people.
Those who understand binary system and those that's don't

2006-08-23 01:13:39 · answer #10 · answered by PC_Load_Letter 4 · 0 0

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