m^5 n^7x times x^3 n^3m^-8?

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2006-08-22 17:27:20 · 5 answers · asked by emily 1 in Science & Mathematics ➔ Mathematics

m^5 n^7x times x^3 n^3m^-8?
m^(5-8) n^(7+3) x^3
m^-3 n^10 x^3

2006-08-22 17:31:54 · answer #1 · answered by Amar Soni 7 · 0⤊ 0⤋

m^5 n^7x times x^3 n^3m^-8?
=m^5 n^7x x^3 n^3m^-8
=m^5*m^-8*n^7*n^3* x^3
=m^5/m^8*n^7*n^3* x^3
=m^-3*n^10* x^3

2006-08-23 05:21:16 · answer #2 · answered by Anonymous · 0⤊ 0⤋

mmm its x^4 not third as the other person said, but otherwise right.

2006-08-23 00:34:05 · answer #3 · answered by who be boo? 5 · 0⤊ 0⤋

SYNTAX ERROR
It's -m^8 not m^-8

2006-08-23 00:36:30 · answer #4 · answered by Kevin H 7 · 0⤊ 0⤋

i,m confused

2006-08-23 00:32:39 · answer #5 · answered by yo 2 · 0⤊ 0⤋