I am really not doing well with these rational expressions and they must be done by thursday and u guys rock so the first to answer right will get points!
2006-08-22 17:07:52 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
figure it out urself cuz i dont know
2006-08-22 17:11:30 · answer #1 · answered by sonjeee 2 · 0⤊ 0⤋
First, remove the prenthases and get
(4x-8)/3 - (2x^2-4)/5
Second, find the common demominator. You'll get:
5(4x-8)/15 - 3(2x^2-4)/15
Once again, remove the prenthases and get:
(20x-40)/15 - (6x^2 - 12)/15
Combine both and get:
(20x - 40 - 6x^2 + 12)/15
Solve above and get:
(-6x^2 + 20x - 28)/15
2006-08-23 00:23:38 · answer #2 · answered by tkquestion 7 · 0⤊ 0⤋
4(x-2) over 3 - 2(x^2-2) over 5
={4x-8}/3 -{2x^2 -4}/5
={5(4x-8) }/15 - {3(2x^2 -4)}/15
=[{20x-40)-(6x^2 -12)}]/15
= {- 6x^2+20x -28}/15
2006-08-23 00:15:52 · answer #3 · answered by Amar Soni 7 · 0⤊ 0⤋
(6x^2+20x-28)/15
2006-08-23 00:16:22 · answer #4 · answered by LoneWolf 3 · 0⤊ 0⤋
Get your teacher to help you.
2006-08-23 00:13:39 · answer #5 · answered by cottoncandyn2000 3 · 0⤊ 0⤋
what class is that anyway? What grade are you in?
2006-08-23 00:15:34 · answer #6 · answered by Nick Name 3 · 0⤊ 0⤋
4(x-2)/3-2(x^2-2)/5
=4x-8/3-2x^2-4/5
=4x-8/-2x^2-1/5
=20x-40/-10x^2-5
=5(4x-8)/-5(2x^2-1)
=4(x-2)/-2x^2-1
2006-08-23 00:14:23 · answer #7 · answered by ph898486 3 · 0⤊ 0⤋