F(as) = (a)/(s^2-a^2)
http://mathworld.wolfram.com/images/equations/LaplaceTransform/inline32.gif
2006-08-22 17:02:10
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answer #1
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answered by gtn 3
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I haven't done Laplace transforms in years (probably last in electrical engineering courses), but I did look it up for you.
According to the book, let f(s) = L{F(t)} be defined as the Laplace transform of F.
Then, for F(t) = (1/a) sinh(at), f(s) = 1/(s^2 - a^2)
I think that gives you your answer.
2006-08-23 00:12:01
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answer #2
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answered by bpiguy 7
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Search for "printable table of Laplace transforms" and I'm sure you'll find what you're looking for. Here's a good link to something that will help you: http://www.efunda.com/math/laplace_transform/forward.cfm?FuncName=Hyper
Try looking around on the site, because they have a wide range of functions that are not on that page.
2006-08-23 00:01:33
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answer #3
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answered by anonymous 7
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If f(t) = sinh(at) then the Laplace Transform of f(t) is
Lap(f(t)) = F(s) = a²/(s²-a²)
Doug
2006-08-23 00:14:43
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answer #4
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answered by doug_donaghue 7
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I am not math master.but I did find a link on Yahoo..
http://www.math.ubc.ca/~burggraf/math215sec101/hw3sol.pdf#search='where%20f%28t%29%20%3D%20sinh%28at'
2006-08-23 00:02:45
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answer #5
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answered by laksh 3
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Did you look between the couch cusions?
2006-08-23 00:00:49
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answer #6
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answered by pwoodrow2354 2
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http://www.mathworld.wolfram.com
2006-08-23 00:01:41
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answer #7
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answered by helixburger 6
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