You guys are SO smart and I really need help!!
2006-08-22 16:54:29 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
I am assuming standard order of operations (Parentheses, Exponents, Multiplication, Division, Addition, Subtraction)
a/b + y/x + 3/2
Multiply a/b by x/x and multiply y/x by b/b. This has the effect of making the denominators of the first and second fractions the same. Now you can add them. (The reason we can multiply by x/x and b/b without altering the equation is that any fraction where the numerator and denominator are both the same non-zero value is equivalent to 1. And multiplying by 1 doesn't change anything)
(ax)/(bx) + (by)/(bx) + 3/2
(ax + by) / (bx) + 3/2
[2(ax + by]) / [2(bx)] + [3(bx)]/[2(bx)]
(2ax + 2by) / (2bx) + (3bx)/(2bx)
(2ax + 2by + 3bx) / (2bx)
2006-08-22 16:57:30 · answer #1 · answered by Pablo Fanques 3 · 0⤊ 0⤋
a / y / 3 + b / x / 2
2006-08-23 00:23:03 · answer #2 · answered by Kevin H 7 · 0⤊ 0⤋
((a*bx2)+(y*bx2)+(3*bx2)) / bx2
bx2*(a+y+3) / bx2
= a+y+3
2006-08-23 00:00:55 · answer #3 · answered by Nick Name 3 · 0⤊ 0⤋