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I am having a little difficulty with this problem. I know it is simple but i just can't get it.

In parallelogram PQRS let

q = vector PQ and s = vector PS

Let U be the midpoint of SR. Extend side SR to a point T such that the length of ST is 2 times the length of SR. I would like to write the following in terms of the vectors q and s.

the ones i have difficulty with are

vector SR
vector SU
vector QU
vector ST

i have also difficulty with

vector PT and
vector TP

2006-08-22 16:54:16 · 3 answers · asked by zz06 3 in Science & Mathematics Mathematics

3 answers

Vectors, of course, have magnitude and direction, but they're not associated with a position. I've drawn your diagram, so here goes (with q and s being vectors):
SR = q
SU = q/2
QU = s - q/2 (draw a parallel line to QU through P to see this)
ST = 2q
PT = s + 2q
TP = -s - 2q

2006-08-22 17:23:32 · answer #1 · answered by bpiguy 7 · 0 0

SR = q

SU = 1/2 * q

QU = s - 1/2 * q

ST = 2 * q

PT = s + 2 * q

TP = - s - 2*q

If you give me the 10 pts ill include a nice diagram.

2006-08-22 17:23:51 · answer #2 · answered by Anonymous · 0 0

element S = (x,y,z) because PQRS is a parallelogram, then vector RS = vector QP RS = OS ? OR = < x, y, z > ? < 3, a million, a million > = < x?3, y?a million, z?a million > QP = OP ? OQ = < a million, 3, 3 > ? < 4, ?2, ?2 > = < ?3, 5, 5 > < x?3, y?a million, z?a million > = < ?3, 5, 5 > x = 0 y = 6 z = 6 S = (0, 6, 6)

2016-12-17 15:36:57 · answer #3 · answered by ? 4 · 0 0

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