This is a simplifying rational expressions problem and help is needed!
2006-08-22 16:49:06 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
5(x - 2) / 3(x - 2) = 5 / 3, x cannot be equal to 2
2006-08-22 17:34:49 · answer #1 · answered by jimbob 6 · 0⤊ 1⤋
5x-10 = 5(x-2)
3x-6 = 3(x-2)
5(x-2)/3(x-2) The x-2 factor cancels out
5/3
2006-08-22 23:53:44 · answer #2 · answered by helixburger 6 · 0⤊ 0⤋
5x-10 = 5(x-2)
3x-6 = 3(x-2)
Let y = x-2
(5x-10)/(3x-6) = 5(x-2)/3(x-2) = 5y/3y = 5/3
Since division by 0 is undefined, the expression is undefined at x=2 (because 3x - 6 = 6 - 6 = 0)
2006-08-22 23:55:27 · answer #3 · answered by Anonymous · 0⤊ 1⤋
(5x - 10)/(3x - 6) = 5(x - 2)/[3(x - 2)] = 5/3
Therefore:
For all real numbers x, where x â 2
(5x - 10)/(3x - 6) = 5/3
2006-08-23 00:04:31 · answer #4 · answered by Jerry M 3 · 0⤊ 0⤋
(5x - 10) / (3x - 6)
[5 ( x - 2 )] / [3 ( x - 2)]
Cancel out the (x - 2) terms (Note: This assumes that x does not equal 2)
5 / 3
2006-08-22 23:50:39 · answer #5 · answered by Pablo Fanques 3 · 1⤊ 1⤋
i think it would be: 5( x-2) over 3( x-2)....then you cancel out x-2 and it leaves you with 5 over 3. Hope its right!
2006-08-22 23:52:27 · answer #6 · answered by Frograid 2 · 0⤊ 1⤋
5/3 everywhere except x=2 (undefined there).
2006-08-22 23:51:17 · answer #7 · answered by Anonymous · 0⤊ 1⤋