How do u simplify this fraction?

Question

z^3 – 3z^2 + z -3 / z^4 - 1

Answer 1

[z^2(z-3) + (z-3)]/[(z^2 - 1)(z^2+1)]

[(z-3)(z^2+1)]/[(z^2-1)(z^2+1)]

(z-3)/(z^2-1)

(z-3)/[(z-1)(z+1)]

Answer 2

- 1/3

Answer 3

first simplify the term before the "/" by grouping terms and taking out a common factor group

z^3 and +z and 3z^2 and -3

= z (z^2+1) -3 (z^2+1)

then take out the take out the common factor in this term

= (z-3)(z^2+1) (top term)

now the term after the "/" is a perfect square

= z^2-1)(z^2+1) (bottom term)

now when you look at the top adn bottom terms ( the terms before and after the "/") their common factor is (z^2+1) this cancels out and your lefte with

z-3 / z^2-1

i think this is the answer

Answer 4

(z^3-3z^2+z-3)/(z^4-1)
then divide both sides by three to seperate the 3z^2
(z^3-z^2+z-3)/((z^4-1)/3)
combinde like terms
(z^2+3)/((z^4+1)/3) and that's as simple as you can get it

Answer 5

For all real numbers z:

[z²(z - 3)+ z - 3]/[(z² + 1)(z² - 1)] = [(z² + 1)(z - 3)]/[(z² + 1)(z² - 1)]

= (z - 3)/[(z + 1)(z - 1), z ≠ -1, z ≠ 1, and z ≠ 3

Answer 6

1/10 or a pinch

Answer 7

ugh. the top appears to be a quadratic. I passed Calc so I wouldn't have to deal with that crap again. I'm outtie.

Sorry man!

Answer 8

I haven't the foggiest. Is there anyone in here that can navigate through this fog? I pray that you don't trip over anything while navigating through this fog.

Answer 9

plug in a value for z then use a calculator

Answer 10

you made that stuff up