5[(12+5)-3(19-14)]
2006-08-22 14:33:46 · 9 answers · asked by Britney I 1 in Science & Mathematics ➔ Mathematics
If you will do your own homework you will learn. Math is fun.
2006-08-26 07:57:09 · answer #1 · answered by carpediem 3 · 0⤊ 0⤋
5[(12 + 5) - 3(19 - 14)] = 5{17 - 3(5)] = 5(17 - 15) = 5(2) = 10
2006-08-23 02:09:13 · answer #2 · answered by Jerry M 3 · 0⤊ 0⤋
5[(12+5)-3(19-14)]
5[(17) - 3(5)]
5[ 17 - 15 ]
5[2]
10
2006-08-22 22:35:04 · answer #3 · answered by Wyle E. Coyote - Super Genius 2 · 0⤊ 0⤋
5[(12+5)-3(19-14)]
becomes 5[17 - 3 * 5]
becomes 5[17 - 15]
becomes 5*2
equals 10
Always perform operation inside innermost parentheses first--the 12+5 and the 19-14, then move out to next thing that sets them apart--the 17 - 3 * 5, in your ques it is brackets, then perform everything outside--the * 5.
Also, always perform multiplication and division first in any equation from left to right--the 3 * 5, then addition and subtraction from left to right -- the 17 - 15, unless the rules above applies about parentheses & brackets.
2006-08-22 21:52:04 · answer #4 · answered by quntmphys238 6 · 0⤊ 0⤋
=5[17-3(5)]
=5[17-15]
=5(2)
=10
2006-08-22 21:37:18 · answer #5 · answered by cooler 2 · 0⤊ 0⤋
5[(17)-3(5)]
5[(17-15)]
5[2]
10
2006-08-22 21:49:42 · answer #6 · answered by funsnuggle 2 · 0⤊ 0⤋
5[(17)-3(5)]
5[(17-15)]
5[2]
10
2006-08-22 21:39:15 · answer #7 · answered by jane 4 · 0⤊ 0⤋
is this for a homework assignment? oooo u naughty girl....lol
2006-08-22 21:42:31 · answer #8 · answered by c h u r r o 3 · 0⤊ 0⤋
jhk
2006-08-26 00:17:24 · answer #9 · answered by greentyce 2 · 0⤊ 0⤋