L has y-intersect (0, -3) and is parallel to the line with the equation y= 2/3x + 1?

Answer 1

y = mx + b

m is the slope, b is the y intercept.

So the new lines is y=2/3x -3

Answer 2

Needs more clarification...

If you mean, what line is parallel to y=2/3+1 with the intersect (0,-3)?

The basic equation is y=mx+b
where m=slope (the degree or steepness of a line)
and where b=y-intersect

If the two lines are parallel, then they have the same slope. In this case, m=slope=2/3
b is the y-intersect, and (0,-3) is the (x,y) intersect, so -3=b=y-intercept.

Therefore, the line parallel to y=2/3x+1 with an intersect of (0,-3) is:
y=2/3x-3