(-3z)=???
to the fifth power for some number z
2006-08-22 09:07:06 · 6 answers · asked by jojojj 1 in Science & Mathematics ➔ Mathematics
-243z^5
2006-08-22 09:35:59 · answer #1 · answered by MollyMAM 6 · 0⤊ 0⤋
Possibility #1
(-3z)^5
= (-3)^5 z^5
= -243 z^5
Possibility #2
(-3z) = z^5
z^5 + 3z = 0
z(z^4 + 3) = 0
z = 0, or z = (-3)^.25 or z = -(-3)^.25
Note: You may need to rephrase your question for clarity.
2006-08-22 17:02:34 · answer #2 · answered by ideaquest 7 · 0⤊ 0⤋
I'm gonna guess that you mean (-3z)^5 for any old value of z.
I'm also gonna guess that the Owners Manual for your calculator disappeared the last time you ran out of toilette paper.
OK.... It's ((-3)^5)*z^5 by the laws of exponents so it becomes
-243*z^5 = -243*z*z*z*z*z
If you can't take it from there, you really **really** have some serious problems.
Doug
2006-08-22 16:20:21 · answer #3 · answered by doug_donaghue 7 · 0⤊ 0⤋
(-3z)^5 = -243(z^5)
2006-08-22 16:14:39 · answer #4 · answered by godmike 2 · 1⤊ 0⤋
-243 * z^5
2006-08-22 16:15:26 · answer #5 · answered by camedamdan 2 · 1⤊ 0⤋
sorry i don't know
2006-08-26 15:21:43 · answer #6 · answered by Anonymous · 0⤊ 0⤋