The answer is in the question... "you get 100 animals..."
100
If you mean how many of each animal, there are three unknowns and only two equations so you need to solve iteratively or by trial and error.
eq. 1: aC + bP + cW = $100
C=Cost of Chickens, P=Costo of Pigs, W=Cost of Cows
a=# chieckens, b=# pigs, c=# cows
eq. 2: a + b + c = 100
One answer would be if you bought 1 cows so c=1.
That means:
aC + bP + cW= $100
a + b + 1 = 100
a = 99 - b
(99 - b)(.5) + b(2.0) = 100
49.5 - .5b + 2b =100
1.5b = 40.5
b = 27
a = 99 - 27 = 72
c = 1
27 pigs, 72 chickes and 1 cow.
2006-08-22 06:41:40
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answer #1
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answered by Anonymous
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Not a good combination. If you get these animals together, they can unleash new strains of viruses into the environment (like SARS etc). Leave out the pigs.
100 animals for $100 is possible with your numbers: 1 cow, 27 pigs, 72 chickens
1 cow --- 10$
27 pig --- 54 $
72 C --- 36$
100 animals --- 100$
2006-08-22 22:22:17
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answer #2
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answered by blind_chameleon 5
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This is a very old riddle. You have the price of the pigs at $2.00, it should be $3.00. no way can this be worked out with the prices you state.
94 chickens at 50 cents each =$47.00
5 cows at $10.00 each = $50.00
1 pig at $3.00
$3.00 + $47.00 + $50.00 = $100.00
94 chickens + 1 pig + 5 cows = 100.
The first and second answers would come out to $105.00
1 cow = $10.00
72 chickens = $41.00
27 pigs = $54.00
$10.00 = $41.00 = $54.00 = $105.00
2006-08-22 07:04:34
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answer #3
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answered by Anonymous
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1 cow, 27 pigs, 72 chickens
2006-08-22 06:52:22
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answer #4
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answered by wazullah 3
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I resemble a cow with horns that curve. I can run up to 40 miles per hour and the males of my species fight for power
2015-07-19 04:55:31
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answer #5
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answered by arnold 1
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72 chix, 1 cow, 27 pigs i think
2006-08-22 06:50:32
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answer #6
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answered by enord 5
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100...duh
2006-08-22 06:43:49
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answer #7
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answered by Andrew H 1
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