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Compare your result with the prediction by displacement equation.

2006-08-22 02:10:16 · 4 answers · asked by Matthew B 2 in Science & Mathematics Mathematics

I don't know how to put this together. Just looking for someone to help me out. Thank you.

2006-08-22 02:11:07 · update #1

4 answers

You wanted an experiment that will yield the time. You never said you wanted to know the time.
Set up two electric eyes attached to a timer clock. one at table height, the second at floor height. drop the marble so that it breaks the beam of the electric eyes. This will measure the time it took for the marble to reach the floor.
The marble will fall at the rate of 384 inches per second/per second. in standard earth gravity. The average table height is 27 inches. so
384:1::27:x = (multiply the extremes of the proportion formula, then solve for x. 27 divided by 384x or 0.0703125 seconds.
By the way, it does not matter if it is a marble a ball bearing a feather or an anvil. Take wind resistance out of the equation and they all fall at the same speed. Our astronauts proved that on the moon.
SandyClaws

2006-08-25 17:32:07 · answer #1 · answered by SANDY CLAWS 2 · 0 0

Sounds like you just need to measure a height of the ground, the marble's mass and the time it takes to hit the floor (depending on which equation you use).

Then just put in the values for gravity, mass, height or whatever is needed in the equation and see if the value you calculate is the same (or close to) the time you measured practically.

2006-08-22 09:28:18 · answer #2 · answered by Stopwatch 2 · 0 0

Assume for this experiment that friction is zero. Make dozen slanting surfaces of same length but making different angles with earth. The angles range from 5 degrees to 90 degrees(right angle).Drop a marble with no friction along the surfaces with no friction. Note the time taken by marble along all the surfaces. Make a graph between angle and time taken. Read the time for a right angle.

2006-08-22 09:26:41 · answer #3 · answered by J.SWAMY I ఇ జ స్వామి 7 · 0 0

cbgn

2006-08-25 23:53:40 · answer #4 · answered by greentyce 2 · 0 0

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