2006-08-21 21:27:33 · 16 answers · asked by del_bos 2 in Science & Mathematics ➔ Mathematics
3t / (9t)^3
=> 3t / 729t^3
=> 1 / 243t^2
2006-08-21 21:44:29 · answer #1 · answered by Ω Nookey™ 7 · 0⤊ 0⤋
3t over 9t
= 3t/9t
divde both sides by 3
=t/ 3t
cancel out the t
=1/3
2006-08-22 04:54:10 · answer #2 · answered by nobodylikesscienceanyways 1 · 0⤊ 0⤋
For all nonzero real numbers t:
3t/9t³ = 3t/3²t³ = 1/3²‾¹t³‾¹ = 1/3t²
2006-08-22 11:46:26 · answer #3 · answered by Jerry M 3 · 0⤊ 0⤋
Do you mean: 3t / 9t³ OR (3t / 9t)³ OR 3t / (9t)³ ?
3t / 9t³ = t / 3t³ = 1 / 3t²
OR
(3t / 9t )³ = (3 / 9)³ = (1 / 3)³ = 1 / 27
OR
3t / (9t)³ = 3t / 729t³ = t / 243t³ = 1 / 243t²
2006-08-22 09:39:32 · answer #4 · answered by Dive, dive, dive 2 · 0⤊ 0⤋
3t/9t = 1/3
2006-08-22 06:49:13 · answer #5 · answered by SAMUEL D 7 · 0⤊ 0⤋
3t/9tcubed = 3t (tpower of 1)/9tcubed (t power of 3)
3/9 = 1/3 ; then t to the first power divided by t to the third power = t to the negative two power (you subtract exponents when you divide) so the answer is 1/3 x t to the -2 power.
2006-08-22 10:07:15 · answer #6 · answered by margarita 1 · 0⤊ 0⤋
THE ANSWER IS 27SINCE 9t/3t=3and 3^3=27
2006-08-22 05:19:00 · answer #7 · answered by vivek 1 · 0⤊ 0⤋
1/ 3t^2
2006-08-22 04:35:19 · answer #8 · answered by iandanielx 3 · 0⤊ 0⤋
1 / 3t^2 is as simplified as you can get it
2006-08-22 09:31:03 · answer #9 · answered by jimbob 6 · 0⤊ 0⤋
1/3t^2
2006-08-22 17:55:21 · answer #10 · answered by CSUFGrad2006 5 · 0⤊ 0⤋