Morning all, are our brains ready to show off
Pythagoras-eum is a new, but as yet unstable Radioactive Source. It is superdense, with a half life of 48 hours. The fatal dose is 20,000Bq.
One day, the college student on work placement decides to injest a sample of this element, which is exactly half of the fatal dose.
Sickness effects occur soon after, meaning he has to leave to Hospital.
Since the Hospital will not release him till he has less than 2% of the original dose, How long will he be in Hospital for?
Remember to show you working, and I shall reveal all later tonight. A nice easy teaser.
Please note that Pythagoras-eum is a fictional element created for the purpose of this question. As always, this question is aimed for our Science geniuses to keep those neurons at top use, compared to some of the annoying questions appearing everyday.
As of a poorly worded question on Monday regarding Forces and Energy, tomorrow AM will have a double show off chance.
2006-08-21 21:15:31 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Physics
He injests 10,000Bq
After 48 hours the radioactive source becomes 5000Bq
another 48 hours 2500 Bq
another 48 hours 1250Bq
another 48 hours 625Bq
another 48 hours 317.5Bq
another 48 hours 158.75Bq
2% of origianal dose is 200 Bq
Total days to the nearest day is 12 days
2006-08-21 21:28:07 · answer #1 · answered by welsh_darkhorse 3 · 1⤊ 1⤋
I am a complete dunce at Math, in fact I find it scary!! But here goes.
It's the half life thing im not sure of so I have doubled the 48 to 96=4 days meaning total time for eradication.
2% of the ingested dose =10,000bq/100*2= 200
10,000/96=104.16 reduction per hour = (less than 2%)
Therefore he would be out of hospital in 4 days.
This is probably totally wrong but every days a school day!
2006-08-21 21:53:41 · answer #2 · answered by kookiboo 3 · 0⤊ 1⤋
If he's in hospital in Ireland, he'll lie on a trolley in a corridor for 32 hours and then be sent home with an appointmnet to see a specialist in 3 years. The appointment will, of course, be cancelled six times. The student will never fully recover and will require full time care. Unfortunately, his family can't afford a nursing home and the government don't care.
2006-08-21 21:22:25 · answer #3 · answered by Taxedman 4 · 0⤊ 1⤋
The half life of the element is 2 days. He took 10,000. He will be released when he has 200. x is the number days.
200 * 2^(x/2) = 10000
2^(x/2) = 50
log50 / log2 = x/2
5.64385619... = x/2
11.28771238... = x
Therefore it will take his almost exactly 11.28771238 to leave hospital.
2006-08-21 22:28:58 · answer #4 · answered by Anonymous · 0⤊ 0⤋
The time in hours for the decay to reach 2% is:
48*(log2(100) - log2(2))
= 48*(6.643856 - 1)
= 270.9051 hours
= 11.28771 days
= just under 11 days and 7 hours.
2006-08-21 22:51:15 · answer #5 · answered by Graham I 6 · 0⤊ 0⤋
It will take about six half-lives for the body dose to decrease to 2% of the original, or just under twelve days.
2006-08-21 21:28:52 · answer #6 · answered by Anonymous · 1⤊ 0⤋
2000 bq wahey just halved them all i think see you tomorrow i am so wrong again.
96 days poor man the man is not in hospital is he? 3500 bq okay the full dose is 96 days. To get out of hospital he needs under 3500bq is 36 hours.
just looking at the other answers i am so wrong thanks anyway
i
2006-08-21 23:03:59 · answer #7 · answered by jules 4 · 0⤊ 0⤋
if it was unstable no one would be able to take it . hey are you good at math? i have a math test tomorrow mind giving me sums on simple logarithms and expansions and factorisations?????????
2006-08-21 21:24:30 · answer #8 · answered by alya-nika 3 · 0⤊ 1⤋
good morning?!?!?!?
good night.
i gotto go to sleep, that's 1:21 AM. too late. my brain is already asleep.
2006-08-21 21:22:31 · answer #9 · answered by ___ 4 · 0⤊ 1⤋