How do you solve Radical equations?

Answer 1

It's hard to answer without an example, so I'll make one up.

sqrt(x+2) + sqrt(x+3) = 5

Square both sides:

(x+2) + 2 sqrt[(x+2)(x+3)] + (x+3) = 25

Now isolate the radical:

2x + 5 + 2 sqrt(x^2 + 5x + 6) = 25
2 sqrt(x^2 + 5x + 6) = 20 - 2x
sqrt(x^2 + 5x + 6) = 10 - x

Square both sides:

x^2 + 5x + 6 = 100 - 20x + x^2
25x = 94
x = 94/25

Not bad for a made-up problem. Let's check the answer.

sqrt(x+2) + sqrt(x+3) = 5
sqrt(94/25 + 50/25) + sqrt(94/25 + 75/25) = 5
sqrt(144/25) + sqrt(169/25) = 5
12/5 + 13/5 = 5
25/5 = 5

The answer checks, and this is a good example of how to solve radical equations.

Answer 2

Like sqrt(2) + sqrt(2) ?

You need to use the radical laws that math people came up with.

Give a specific equations and I'll give specific answers.

Answer 3

if you have one radical, get everything else on the other side and square both sides (and verify that solutions work).

if you got like a sum of 2 radicals, you're outta luck.

Answer 4

you should take out the square root sign by squaring both sides of the equation :)

or something like that

Answer 5

Simply by squaring both sides

Answer 6

I don't. I ask someone to solve it for me.