if a wine is 12 percent (v/V) ethanol, how many mililiters of ethanol are present in a glass containg 120 mL .

Question

120 mL of the wine

Answer 1

120 mL * 12% ethanol = 14.4 mL of ethanol

Answer 2

The term volume / Volume means, you have to consider volume percent. I mean both the solute (ethanol) and solvent (water) are liquid, so you can measure them in volumes rather than weight.

v/V % means how many ml of solute is present in 100 ml of solvent. For example 10 % (v/V) means, 10 ml of ethanol is present in 100ml if wine and the ather 90 ml is water.

Similarly 12% v/V means 12 ml of ethanol is there in 100 ml of wine, i.e. 12 ml of ethanol and 88 ml of water.

In 12% of 120 ml of wine we have to find out as
1% = 120 ml/ 100 = 1.2 ml
12% = 12*1.2 ml = 14.4ml

Or else (120/100)*12 = 14.4 ml of ethanol in 120 ml of wine
Also 120 - 14.4 = 105.6 ml water

Answer 3

concentration of a solution = amount of solute/ amount of solution
X 100%

=>12% = (amount of ethanol/ 120 mL) X 100%
=> 12 =( amt. of ethanol /120 ) X 100 mL
=> 12 = (100 X amt. of ethanol )/120 mL
=> (12 X 120 mL)/ 100 = amt. of ethanol
=> amt. of ethanol = 1440/100 mL
=> amt. of ethanol = 14.4 mL

Answer 4

120 ml of wine contains 14.4 ml of ethanol.

Answer 5

12% * 120 mL = 14.4 mL

Answer 6

volume percent of solute = (vol. of solute / vol. of soln.) *100
so vol of solute = (vol percent * vol of soln.)/100
= (12 * 120) / 100
= 1440 / 100= 14.4 ml

Answer 7

120 DIVIDED BY 100 IS 1.2 TIMES 12 IS 14.4ML

Answer 8

14.40 ml of ethanol

Answer 9

14.4 ml

Answer 10

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