2006-08-21 16:57:27 · 7 answers · asked by Anonymous in Education & Reference ➔ Homework Help
f(a+1) = 3(a+1) + 3
= 3a + 3 + 3
= 3a + 6
= 3(a+2)
2006-08-21 17:53:59 · answer #1 · answered by rejected_pen87 2 · 0⤊ 0⤋
You replace every x in the function with a+1:
f(a+1) = 3(a+1) + 3
f(a+1) = 3a + 3 + 3
f(a+1) = 3a + 6
2006-08-21 17:06:20 · answer #2 · answered by Roz 1 · 0⤊ 0⤋
Plug in a+1 wherever x is
F(a+1) = 3(a+1) + 3
F(a+1) = 3a +3 + 3
F(a+1) = 3a + 6
you could say f(homework) = 3homework +3
2006-08-21 17:05:16 · answer #3 · answered by mollyneville 5 · 0⤊ 0⤋
f(a+1) = 3(a+1) + 3
f(a+1) = 3a + 3 + 3
f(a+1) = 3a + 6
2006-08-21 17:56:38 · answer #4 · answered by -xue- 3 · 0⤊ 0⤋
3a+6
2006-08-21 17:03:25 · answer #5 · answered by kengoward 3 · 0⤊ 0⤋
its simple...u plug in a+1 for x and get 3(a+1) +3 and then 3a+3+3 then 3a+6
f(x)=3a+6
2006-08-21 17:05:30 · answer #6 · answered by Anonymous · 0⤊ 1⤋
i think its 6a+6 because 3(1)+3=6 and if x was 1 then f would be 6 and if that's true then 6(a+1) would be your new equation and 6a+6 would be your answer
2006-08-21 17:06:54 · answer #7 · answered by ~♥~Nay~♥~ 3 · 0⤊ 0⤋