When x3+3x2-2x+7 is divided by x+1, the remainder is:
7
8
9
11
13
???
2006-08-21 16:33:11 · 17 answers · asked by azmattaz06 2 in Science & Mathematics ➔ Mathematics
If you set this up as a long division problem with x+1 on the outside and x^3 + 3x^2 - 2x + 7 inside and solve it like a long division problem, you will have x^2 + 2x - 4 on the top and a remainder of 11. The remainder part is the leftover after the long division - no need to put it over x+1 (when you have 14 divided by 5, you have 2 remainder 4, not 2 remainder 4/5).
2006-08-21 16:40:13 · answer #1 · answered by Bad Boy 2 · 1⤊ 0⤋
7
2006-08-22 06:01:28 · answer #2 · answered by Anonymous · 0⤊ 0⤋
7
2006-08-21 23:43:27 · answer #3 · answered by Don M 7 · 0⤊ 1⤋
11
2006-08-21 23:41:59 · answer #4 · answered by Michael M 6 · 0⤊ 0⤋
x^3+ 3x²-2x + 7 divided by x+1 = x² + 2x - 4 and remainder or 11.
2006-08-22 04:16:51 · answer #5 · answered by Brenmore 5 · 0⤊ 0⤋
I ended up with 7
2006-08-22 10:51:27 · answer #6 · answered by Mann 2 · 0⤊ 0⤋
x^3 + 3x^2 - 2x + 7 = (x+1)(x^2 + 2x - 4) + 11
Remainder is 11
2006-08-21 23:48:54 · answer #7 · answered by Anonymous · 0⤊ 0⤋
4/5
2006-08-22 01:13:34 · answer #8 · answered by -xue- 3 · 0⤊ 0⤋
it is f(-1)=7
2006-08-21 23:40:52 · answer #9 · answered by raj 7 · 0⤊ 1⤋
i donno if u know about synthetic division but it goes like this if u dont it might be confusing(i used the dots to make space because it doesn't make sense if i just put alot of spaces because it'll all come together and make it look wrong, but just imagine as the dots as empty spaces):
-1| 1.....3.....-2......7
.........>-1....>3...> 6
.....1>^ -3>^ -6>^ 42
if u see how it works then the function you are left with is x^2-3x-6 + 42/(x^3+3x^2-2x+7)
2006-08-21 23:52:02 · answer #10 · answered by ParadoxZero 3 · 0⤊ 0⤋