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This is a tension based problem:

Ftens = (4535.9 N) / [sine (30 degrees)] = ?

2006-08-21 16:01:02 · 3 answers · asked by likestoplaywithsquirrels 3 in Science & Mathematics Mathematics

3 answers

Ftens=4535.9N/sin30*
=4535.9N/(1/2)
=4535.9*2N
=9071.8N

2006-08-21 16:39:53 · answer #1 · answered by raj 7 · 0 0

Looking for the tension in a straight member supported at an angle of 30 degrees to the horizontal. Sine of 30 degrees is 0.5000 exactly; you do the math.

2006-08-21 23:10:28 · answer #2 · answered by Anonymous · 0 0

9.0718N=Ftens

2006-08-21 23:09:19 · answer #3 · answered by matty 1 · 0 0

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