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Hi dear.
May be my question sounds stupid to u but I am intrested to know it.
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If a DC Generator is rotating and genertating electricity, for a DC motor.these energies are going to motor by two wires (possitive and negative).Now consider if we cut one of the wires of DC generator for example thepossitive one, the Motor will be stoped of rotating but the Generator is still runing, Now I want to know where all those currents and energies generated by the DC generator are going?

2006-08-21 15:20:29 · 3 answers · asked by Great Man 1 in Science & Mathematics Physics

3 answers

In order for power to be transferred to a load voltage and current must be delivered to it.
By removing the connection to the motor as in your scenario the voltage will still be present at the generator but there is no path for current to flow. Without current flow the voltage cannot leave the wire and get to the load (motor). The voltage potential will simply remain at the end of the wire until the generator coasts down, reducing as is slows.
This is much the same as removing the battery from a circuit by opening a switch or taking out the battery. The energy remains in the battery until there is a path for it to flow through.

2006-08-21 15:37:15 · answer #1 · answered by Buffertest 3 · 0 0

As stated in Ohms law, a path for electron flow must be intact or the flow of electrons stops as they cannot complete the requirements for the formula E = I X R.

The electrons just lay there going nowhere. It's like someone blew up their bridge and you got a traffic jam and not going anywhere until someone reconnects the cut wire, which again provides a path for current flow.

The flow would be rated in amperage (As current flow) and the amperage is based on the formula I = E/R where I= current flow, E = Voltage, and R = Resistance (Of the wire) but it is cut so the R factor is missing, hence no electron flow, therefore DC motor no workey. It all goes back to the DC Generator still turning but cannot output anything because of the cut connection.

We could go much deeper ie, The Inductive Reactance Factor but why not keep it simple, clear and understandable.

You question is not stupid, it is a good, valid question. The only stupid question, is the question that is never asked.

I hope I answered it sufficiently for you.

Thank you for your question,
Darryl S.

2006-08-21 22:50:15 · answer #2 · answered by Stingray 5 · 0 0

a generator develops a potential (a voltage) not necessarily a current (if there is no place for the current to flow)

the water analogy is often useful, because water is more intuitive and we can see it

a pump is analagous to the DC motor, the water flow analoguous to the electrical current, and the water pressure analagous to the electric voltage

now if we have a pump working along circulating water from your swiming pool through a filter and back into your pool

if we close a valve at the discharge of the pump, then the water stops flowing, there is no water flow, the pressure at the pump discharge remains high

if you have a generator being turned with no load, it is easy to turn and it maintains a voltage (like a pressure) on the output leads

if you connect a load, like a light or motor or whatever, then the current begins to flow, and the generator gets much harder to turn, because now it is doing work, generating actual power, not just potential power, not just maintaining a voltage against minimal losses

so, to answer you question, there is very little energy generated by a generator under no load (nothing connected), the little bit of energy generated makes up for heat losses and dissipation of voltage through the air or other losses

so, no energy is generated, so it isn't going anywhere

2006-08-21 22:31:54 · answer #3 · answered by enginerd 6 · 1 0

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