Simplify (9x2y3z-12xy2z2)/3yz?

Question

explain please.

3x2y2 - 4xyz?
Reads....3x to the second y to the second-4xyz

Answer 1

That can be two way different things....or 3 actually...maybe 4 or 5 depending on what exactly the equasion is being divided into.

That can either be nine x to second y to third z minus twelve times x times y to second z to the second divided by 3 times y times z

or nine x to the second y to the third z minus twelve x y to the second z to the second divided by 3 times y times z or just divided by 3 y z..

On all of my answers, I didn't get anywhere near 3x^2y^2-4xyz

Remember, that each variable is the same meaning, 3x and 4x... x is the same variable, so it needs to be simplified. And by doing that, it must go to the first number.. or actually the first side of the equasion. ie: the left, unless using scientific negotiation(s) in quadratic equasions or the such, --OR-- specifying the configuration accordingly by using operational sigma's to indicate standard plus or minus diviations....

Here's an example...

A model of the quantity.. in question by a normal distribution and estimate lower and upper limits:

a- and a+ such that the best estimated value of the quantity is (a+ + a-)/2 (i.e., the center of the limits) and there is 1 chance out of 2 (i.e., a 50 percent probability) that the value of the quantity lies in the interval a- to a+. Then uj 1.48 a where a = (a+ - a-) /2 is the half-width of the interval.

That's a new subject though and I'm getting off track...okay, so your question...

Here is as follows, periods are spacing only:

..........( 9x^2y^3z - 12xy )....... ( 81xy^3z - 12xy )
....... - - - - - - - - - - - - - - = - - - - - - - - - - - - - - -
.................... 3yz . . . . . .. . . . . . . . 3yz

.......... ( 81xy^3z - 12xy )....... ( 531,441xyz - 12xy )
....... - - - - - - - - - - - - - - - = - - - - - - - - - - - - - - -
.....................3yz . . . . . . . . . . . . . . . 3yz

.......... (531,441xyz - 12xy)
....... - - - - - - - - - - - - - - - - = 177,143x^2y^3z^2
.....................3yz

However, I highly doubt that was the answer to that...unless you made it up.

So, I'll do the other choice-- the one that a textbook might have:

........( 9x^2 * y^3 * z - 12xy )......( 81 * y^3 * z - 12xy )
...... - - - - - - - - - - - - - - - - - = - - - - - - - - - - - - - - - -
.................... 3yz ......................... . . .. 3yz

........ ( 81 * y^3 * z - 12xy )....... ( 81y^3 * z - 12xy )
...... - - - - - - - - - - - - - - - - - = - - - - - - - - - - - - - - -
.................... 3yz.............. . . . . . . . ... 3yz

........ ( 81y^3 * z - 12xy ) ....... ( 81y^3z -12xy )
...... - - - - - - - - - - - - - - - = - - - - - - - - - - - - - -
................... 3yz ... . . . . . . . . . . ...... 3yz

......... ( 81y^3z - 12xy )
....... - - - - - - - - - - - - - - = 27y^3z^2 - 12xy^2
.................... 3yz

..................... . . . . . . . . . . . . . .. 12xy^2
27y^3z^2 - 12xy^2 = 27y^3z^2 - ----------------
....... . . . . . . . . . . . . . . . . . . . .... {0.0^y^-1}

Negative 1 because yz is being divided into y^3 and z^2.

Hope this makes sense... Next time, try to detail your equasion(s).

--Rob :)

Answer 2

multiply the numbers to get a product
(9*2*3)xyz - (12*2*2)xyz =

54xyz - 48xyz= (54-48)xyz=6xyz

now divide by 3yz

6xyz/3yz=2x...the y and z cancel out during the division process.

so 2x is the answer...

now, if the equation was equal to zero, then...

2x=0...divide both sides by 2 and x=0

Answer 3

You're not using exponent symbols in the questions, are you?
Well, I think you want the answer of:
3x^2y^2-4xyz

Divide the coefficients...subtract the y and z exponents in the numerator by the exponents in the y and z in the denominator.

Answer 4

(9x^2y^3z - 12xy^2z^2)/(3yz)

((3yz)(3x^2y^2 - 4xyz))/(3yz)

ANS : 3x^2y^2 - 4xyz

Answer 5

used to be able to 9x2y5z-12xy23yz i think thats it not sure though