i did this crap in algebra 1 and geometry but i forgot how to do it.....i havent started schoool yet.....my friend jus called me because i think that she was trying to be prepared for the math that she has the semester. Please help me figure out how to do this because i have forgot!!!!!
2006-08-21 12:12:00 · 6 answers · asked by singing_piano24 1 in Science & Mathematics ➔ Mathematics
1st you can do the x
4x + 2y = 98 --------- 1
4x = 98 - 2y
x = 98 -2y / 4
Then... you can replace the x into the question
4 (98-2y/4) + 2y = 98
98 -2y +2y =98
98 = 98
y =98
2006-08-21 21:20:59 · answer #1 · answered by ayie 2 · 1⤊ 9⤋
Bazzmc is right -- with only one equation, you can solve for either variable in terms of the other, but you won't get a purely numeric answer for either x or y.
For instance, to solve for x, we need to take steps to isolate x on one side. Let's start by subtracting 2y from both sides:
4x = 98 - 2y
Then, we divide both sides by 4:
x = 98/4 - 2y/4
Simplifying,
x = 49/2 - y/2
or x = (49 - y) / 2
You can solve the original equation for y in a similar way. Hope that helps!
2006-08-21 12:22:06 · answer #2 · answered by Jay H 5 · 3⤊ 0⤋
You need to make a T chart, X on one side and Y on the other. You pick a number to be X, for example 1. Then you plug the 1 in for the X in the equation and you solve for Y. It should look like 4(1) + 2y =98, 4+ 2y =98, then you subtract 4 from 98. 2y =94. then you divide 94 by 2 and you get 47 for y. And that is it.
2006-08-21 12:26:17 · answer #3 · answered by Anonymous · 2⤊ 1⤋
there are two way s to approach a problem like this...
1) you need another equation of x and y ... if you have that then you solve them simultaneously and the answer is A point where the two lines intersect.
2) you play the guessing game. you guess a X value and then calculate an y (or guess a Y and calulate an X) usually it is called a T chart something like this
X ( guess)............................... Y (calculate)
0................ then 2y=98, y = 98/2, y= 49
-1................then -4 +2y =98, 2y= 98+4, 2y=102, y=102/2, y=51
1.................the 4 +2y =98, 2y=98-4, 2y = 94, y=94/2, y= 47
so possible answers are (0, 49),(-1,51),(1, 47) the list of possibilities is endless
2006-08-21 13:20:53 · answer #4 · answered by Charity 3 · 1⤊ 0⤋
4x + 2y = 98
2y = -4x + 98 (Divide each by 2)
y= -2x + 49
y = -2(4)+ 49
y= -8 + 49
y=41
4x + 2(41) = 98
4x + 82 = 98
4x = 98-82
4x = 16 (Divide each by 4)
x = 2
2014-08-31 08:19:04 · answer #5 · answered by Anonymous · 0⤊ 0⤋
2y = 98 - 4x
y = 49 - 2x
4x = 98 - 2y
x = 24.5 - .5y
2006-08-21 15:14:52 · answer #6 · answered by lager57 4 · 1⤊ 0⤋
This is an equation for a line, and doesn't have a unique solution.
You can re-formulate in the following way:
y= -2x + 49
When this line is graphed, it gives you a graphic representation of all the combinations of X & Y that are solutions to the equation.
2006-08-21 12:19:26 · answer #7 · answered by Kerintok 2 · 2⤊ 0⤋
The number of solutions is infinite. You need a second equation. The single equation is that of a line, going on forever in two directions with an infinite number of points comprising the line. Each point is a solution.
2006-08-21 13:36:23 · answer #8 · answered by davidosterberg1 6 · 2⤊ 0⤋
Solve For X And Y
2016-10-06 01:24:03 · answer #9 · answered by geissel 4 · 0⤊ 0⤋
That equation has two unknowns. You need a second equation to solve for both x and y. Otherwise, you have to solve for x in terms of y, or for y in terms of x.
2006-08-21 12:18:25 · answer #10 · answered by bazzmc 4 · 1⤊ 0⤋
y= -2x+49
x= -1/2y+24.5
2006-08-21 12:21:07 · answer #11 · answered by Archangel 4 · 2⤊ 0⤋