3x + y = 6
3x - y = 0
2006-08-21 10:07:25 · 6 answers · asked by wicked 1 in Science & Mathematics ➔ Mathematics
Add the two equations together:
3x + y = 6
3x - y = 0
(3x + 3x) + (y - y) = (6 + 0)
6x + 0 = 6
x = 1
3x + y = 6 ----> 3(1) + y = 6
y = 3
Coordinate is: (1,3)
2006-08-21 10:32:30 · answer #1 · answered by Anonymous · 0⤊ 0⤋
add the equations...
3x + y = 6
3X - y = 0
--------------
6x + 0 = 6
X=1!
If x=1 the 3x+y=6 becomes
3(1) + y = 6
3 + y = 6
y = 3
2006-08-21 10:29:44 · answer #2 · answered by dbexon 1 · 0⤊ 0⤋
3x+y=6 or 3x=6-y
3x-y=0 or 3x=y
therefore, y=6-y or 2y=6 or y=3
and
3x+3x=6 or 6x=6 or x=1
2006-08-25 08:21:42 · answer #3 · answered by Anonymous · 0⤊ 0⤋
are you asserting x^a million -x^2 = 0 ? then x(a million-x)=0 then x=0 or a million-x=0 then x = 0 or x = a million are you asserting 3x^a million - 2x^2 = -a million? then a million + 3x - 2x^2 = 0 then -2x^2 +3x + a million = 0 no longer able to ingredient, use the quadratic formulation -b + or - (sqrt(b^2-4ac))/(2a) so plug in a = -2 b = 3 c =a million
2016-12-11 12:46:23 · answer #4 · answered by ? 4 · 0⤊ 0⤋
y = 6 - 3x
y = 3x
so
3x = 6 - 3x
6x = 6
x = 1
if you plug that in to one of the previous equations,
y = 3(1) = 3
so the coordinates are (1,3)
2006-08-21 10:28:46 · answer #5 · answered by Liz B 1 · 0⤊ 0⤋
3x + y = 6
3x - y = 0
6x = 6
x = 1
3x - y = 0
3(1) - y = 0
3 - y = 0
-y = -3
y = 3
ANS : (1,3)
2006-08-21 11:28:30 · answer #6 · answered by Sherman81 6 · 0⤊ 0⤋