what is 9<3x+6<15?

1 ⤊

2006-08-21 08:22:00 · 7 answers · asked by Anthony M 1 in Science & Mathematics ➔ Mathematics

9 < 3x + 6 < 15

Subtract 6 from each expression

3 < 3x < 9

Divide each expression by 3

1 < x < 3

2006-08-21 08:45:28 · answer #1 · answered by Anonymous · 1⤊ 0⤋

9 < 3x + 6 < 15
9 < 3(x + 2) < 15
3 < x + 2 < 5
1 < x < 3

2006-08-21 09:34:14 · answer #2 · answered by Sherman81 6 · 0⤊ 0⤋

2006-08-21 08:39:53 · answer #3 · answered by Marc B 3 · 0⤊ 1⤋

9<3x+6 => 3 < 3x => 1 3x+6 < 15 => 3x < 9 => x <3

so,

1

2006-08-21 08:32:29 · answer #4 · answered by AresIV 4 · 0⤊ 1⤋

answere = 2
u can do this
9<3x+6<15 --> 9 - 6< 3x+ 6 - 6< 15 -6
so u have: 3<3x<9 and x can be {2}

2006-08-21 09:07:06 · answer #5 · answered by siavash 1 · 0⤊ 1⤋

x=2. 3x2=6. 6+6=12 12 is >9 but <15.

2006-08-21 08:31:08 · answer #6 · answered by hugetacoboy 1 · 0⤊ 1⤋

I agree with sherman and the solutions depends what kind of numebr is x:integer (x=2), decimal...

2006-08-25 08:03:05 · answer #7 · answered by ? 3 · 0⤊ 0⤋