throw 1 penny 2400 times. (probability for tails=0,4). probability for 960 tails times.?

Question

a.17% b1,7% c.3,4% d.2,4%

Answer 1

P = C(2400, 960) · (0.4)^960 · (0.6)^1440.

= (5.0729297 × 10^699) · (9.4971145 × 10^-383) · (3.4498527 × 10^-320)

= 0.01662, or about 1.7%... it's (b).

Answer 2

relies upon -- do you mean precisely 6 circumstances, or a minimum of 6 circumstances? Assuming you mean precisely 6 circumstances, we can actual answer the equivalent question: what's the risk that precisely 2 of the throws arise heads? variety the throws one million-8, and evaluate the opportunities: * the first of both heads might want to be Toss #one million; the different head is then one in each and every of the different 7. (it truly is 7 opportunities.) * the first of both heads might want to be Toss #2; the different head is then one in each and every of the different 6. * the first of both heads might want to be Toss #3; the different head is then one in each and every of the different 5. interior the top, we've 7+6+5+4+3+2+one million = 28 different opportunities for 2 heads. considering there are 2^8 = 256 entire ideas to toss a coin 8 circumstances, our risk of two heads is hence 28/256, or 7/sixty 4. wish that facilitates!

Answer 3

What if I call the Head - Tail and the Tail - Head?

Answer 4

I think "b" is the answer.

Answer 5

a)