what is the relationship between the volumes of a sphere, cylinder and a cone?

Answer 1

The Radius and Pi

Volume of a cone = 1/3 π r^2 h
Volume of a cylindar = π r^2 h
Volume of a sphere = 4/3 π r^3

Answer 2

thinking a community producing function G(x), the blunders bounds for Simpson's rule is: ? ? (a million/ninety)h^5 G[4](x*); the place G[4] is the fourth by-product with appreciate to x of G(x), and x* provides the close by optimum for the fourth by-product. consequently, on the needed era, if the fourth by-product is *everywhere 0* then, for sure, Simpson's rule provides a precise value. (Edit: in deference to Dr. D's remark, the fourth by-product of a cubic polynomial or decrease is often 0......) In mathematical words, this may be a "sufficient" situation, yet no longer a "needed" one. it extremely is nevertheless plausible for the *truthfully blunders* to be 0, whether the *blunders bounds* at the instant are not. of direction looking the *truthfully* blunders, might in all likelihood require integrating to locate the right quantity of the forged..........which completely defeats the objective of utilising the form of formulation interior the 1st place. ~W.O.M.B.A.T.

Answer 3

The radius of each can be same. Pi is always there.