If you have a eutectic mixture... melting won't work.
The eutectic tin-lead alloy is made up of 63% tin and 37% lead. It melts at 361° Fahrenheit (183° Celcius).
The melting point of an alloy is often quite different from the melting points of the pure metals from which it is made.
Tin melts at 447.8° F (231.8° C).
Lead melts at 620.6° F (327.5° C).
Pure substances have a sharp melting point. A pure substance is either an element, or a chemical compound. Mixtures melt over a range of temperatures.
A eutectic alloy is one that has a sharp melting point.
2006-08-21 02:20:17
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answer #1
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answered by Charity 3
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The easiest way to separate Tin from lead is to heat the alloy slowly. At 505.08 K (231.93 °C, 449.47 °F), the parts of alloy will start liquefying. This melting portion of the alloy is Tin. Keep the temperature above 505.08K but below 600.61 K (327.46 °C, 621.43 °F) and drain out the Tin (melted portion of metal). Melted Tin should "float" at the top because it is lighter than Lead and alloy. Once you drained out all the metal that melts at the temperature range described above, cool the alloy and repeat to completely separate Tin from Lead. Just remember to keep the temp below 600.61K because at that temperature, Lead will start melting as well.
2006-08-21 02:17:56
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answer #2
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answered by †ђ!ηK †αηK² 6
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The melting points and densities of tinand lead are different. To separate the metals from the alloy: Heat the alloy to melt. Maintain the temperature to 330 C. The molten metals will separate into layers. The tin on top of the lead. You can ladle the tin from the top or scoop lead from the bottom.
Or slowly cool down the molten alloy toabout 240 C. The lead will solidfy on the bottom of the molten tin.
Sn. mp= 232 C. density=7310 kg/cu.m
Pb. mp= 327 C density=11340 kg/cu.m
This applies to non-eutectic alloy.
2006-08-21 02:25:40
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answer #3
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answered by cherox 3
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their melting points are different.
2006-08-21 01:12:31
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answer #4
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answered by ? 6
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i dont know!!!!!!!!
LOL!
just trying to make points
2006-08-21 02:26:22
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answer #5
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answered by Navdeep B 3
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