no, only when a=b (and b is not 0)
Example: a=3, b=5
(3+7)/(5+7) = 10/12 = 5/6
5/6 is not the same as 3/5.
The sevens don't cancel because they are added, not multiplied, to the variables in the numerator and denominator.
2006-08-20 22:39:35
·
answer #1
·
answered by phaedra 5
·
1⤊
0⤋
a+7 over b+7 only equals a over b if a and b are the same number. Also you need to make sure that the denominator is never 0. This happens only when b = -7 (in a+7 over b+7),
or b = 0 (in a over b).
Try this yourself and it will make sense..
2006-08-20 22:54:28
·
answer #2
·
answered by Rozz 3
·
0⤊
0⤋
No. I chose A=3 & B=5.
3+7 10 5 3
----- = --- = --- DOES NOT EQUAL ----
5+7 12 6 5
2006-08-20 22:39:24
·
answer #3
·
answered by Redeemer 5
·
1⤊
0⤋
Nope. take a=3, b=6. then the top becomes 10, bottom is 13. 10/13 is not equal to 3/6
2006-08-20 22:35:05
·
answer #4
·
answered by jakethesnake23a 2
·
1⤊
0⤋
I would say No. I believe that a+7 over b+7 should cancel each other out, and equal 1 (or 1ab)
a+7= 7a; b+7=7b; therefore 7a divided by 7b =1ab.
2006-08-20 22:48:08
·
answer #5
·
answered by reverend_logan 2
·
0⤊
1⤋
Nah.
Adding the same numbers changes the fraction.This is true only in the case of multiplying or dividing the same number.
2006-08-21 02:04:21
·
answer #6
·
answered by Anonymous
·
0⤊
0⤋
if a and b does not correspond to any number, then a over b is correct.
2006-08-21 04:30:30
·
answer #7
·
answered by Iya 3
·
0⤊
0⤋
no. Try it with a few numbers, with a and b the same and with a and b different.
2006-08-20 22:35:27
·
answer #8
·
answered by Goddess of Grammar 7
·
1⤊
0⤋
Yes because the seven cancels out.
2006-08-20 22:35:24
·
answer #9
·
answered by David W 4
·
0⤊
4⤋