find values for A,B and C so that this calculation is correct ? ABC+ACB=CBA?

Answer 1

C=9, A = 4 and B=5

ABC+ACB = CBA

459+495 = 954

Answer 2

A=1 B=0 C=-1

Answer 3

There are different answers: If ur question is by adding the value of A,B and C, the answer can be :A>1 B>0 C>1 or all 0 or either one of A,B or C is 0.(A>0+B>0+C>0=0 A>0+C>0+B>0=0 C>0+B>0+A>0 0+0+0=0)
If ur question is the values putting together,: A>4 B>5 C>9 (ABC>459+ ACB>495 = CBA>954)

This caculation works!

Answer 4

A = 0 B = 0 C = 0

Answer 5

Order of operations, people....

ABC+ACB=CBA is the same as:
(ABC)+(ACB)=CBA

So, as long as one of the variables is zero, the other two can be any value. The order of operations calls for multiplication before addition, so you first find the product of ABC and ACB before adding them together. If one of the variables is zero, then the two products are automatically zero. Also, this makes the product of CBA = 0. Thus, 0+0=0

Answer 6

A = 0, A = 0, C = 0

Answer 7

the complete answer is like this:

ABC + ACB = CBA
this means an equation with 3 paramethers.

1) the first case, when C+B<10, B+C<10:
C+B = A
B+C = B
A+A = C

C=A-B
B+A-B=B
A+A=A-B

C=A-B
A=B
A=-B

Now, we have this impossible thing of A being equal to B and also being equal to minus B. This has only one answer, if and only if A=B=0. Which means C=0 also.


2) second case, when C+B>10

C + B = 10 + A
B + C +1 = 10 + B
A + A +1 = C

C=10+A-B
B+(10+A-B) +1 = 10+B
A+A+1 = 10+ A-B

C=10+A-B
B-B-B +A=10-10-1
A+A-A+B=10-1

C=10+A-B
-B+A= -1
A+B = 9


C=10+A-B
A= -1 + B
-1 + B + B = 9

C=10+A-B
A= -1 + B
2xB = 10

therefore, B=5.

A = -1 +5
A = 4
and

C= 10 + 4 - 5
C = 14 - 5
C = 9

Other cases, besides those two cannot be, so the complete answer to your question is:

1) A = B = C = 0
2) A = 4, B = 5 , C = 9

Answer 8

The only solution is A = B = C = 0
Otherwise
if A = 1 , for instance, C should be 2 ...... than C + B = 2 + B = A = 1....which is impossible, cause neither one of A, B or C can be < 0

if B = 1, than you will have
B + C = 1 + C = C
and B + C = 1 + C = B
which is also impossible

Same thing if C = 1...

.....If A, B or C = 2, 3, 4,......9

you will still get impossible situations

So A = B = C = 0 is the only solution to your problem
000 + 000 = 000

Answer 9

or A=1, B=1, C=1.

Answer 10

Either A=0 or B=0 or C=0

Answer 11

A = 012348737529857349857349530123890124790213479082147
091834729108472910847012947398217429103470923184702
194729013472091347210934721904729013472913479021347
291034721903472109347213095723918743920847329875120
935719820346123895618948532865027436505325732659236
50215612931561293651029562610

B = 130485561275623639175219816429837549821364982316203
986839247329638946489034924372856128394721389641238
947238956829340398328418438984937286328946238947238
963824623807230838495243893947387894894894098523859
854124289974289462984689489568427498258941704985890
56198

C = 0