2006-08-20 18:45:43 · 6 answers · asked by soulsistertie 1 in Science & Mathematics ➔ Mathematics
You can't use 44 in there. It says using four fours, meaning the number four, not digits (note the four separate fours in the parentheses).
For the sake of thinking outside the box, using four 4's to get 11 is easy in bases other than ten:
In base five: (4+4)/4+4 = 11
In base six: 4+4-4/4 = 11
In base seven: 4+4+4-4 = 11 (also 4*4-4-4 = 11)
In base eight (octal): 4+4+4/4 = 11
In base nine: (4!+4*4)/4 = 11
In base eleven: 4!-4-4-4 = 11
In base twelve: (4!+4!+4)/4 = 11
In base thirteen: 4!/4+4+4 = 11
In base fourteen: 4*4-4/4 = 11
In base fifteen: 4*4+4-4 = 11
In base sixteen (hexadecimal): 4*4+4/4 = 11
In base seventeen: (4!+4!+4!)/4 = 11
But if you're just dealing with base ten then it's:
(4!+4!-4)/4 = 11
*also: (4!+4)/4+4 = 11
Note: This was completed at 12:37AM MST, 21/08/06.
*Note: Second answer completed at 12:45AM
2006-08-20 19:09:47 · answer #1 · answered by CubicMoo 2 · 0⤊ 0⤋
That won't work, you added a 2 into it. (still working...)
Hmm.. I can give you All the numbers from 0 to 10. But 11 is stumping me.
0 = 44-44
1= 44/44
2=4/4 +4/4
3= (4+4+4)/4
4= 4 + (4-4)/4
5 = [(4x4) +4]/4
6 = (4+4)/4 +4
7 = 44/4 -4
8 = 4+4+4-4
9 = 4+4 +4/4
10 = (44-4)/4
Using 3 fours
11 = 44/4
Using 5 fours
11 = 44/(4*4/4)
It's two in the morning, my brain hurts. I give up.
2006-08-21 01:58:01 · answer #2 · answered by goodlittlegirl11 4 · 0⤊ 0⤋
Here's a solution:
4!!+4-(4/4)=8+4-1=11,
where !! means double factorial.
2006-08-21 03:04:37 · answer #3 · answered by angyansheng65537 2 · 0⤊ 0⤋
4+4+4-(4/4)
2006-08-21 01:59:56 · answer #4 · answered by Mara 1 · 0⤊ 0⤋
4^2 - 4 - (4/4)
That two is an exponent. If you feel that counts as a 2, then by all means, try to find another way.
2006-08-21 01:51:40 · answer #5 · answered by Master Maverick 6 · 1⤊ 0⤋
(4!*sqrt(4)-4)/4 = 11
2006-08-21 03:16:11 · answer #6 · answered by ideaquest 7 · 0⤊ 0⤋