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9 answers

substituting x into -2:
3(-2)^2-5(-2)+4
=3(4)+10+4
=26

2006-08-20 17:00:18 · answer #1 · answered by Marushka 2 · 0 0

3 * x^2 - 5 * x = 4 =; where x = - 2=> 3 (-2) * (-2) - 5 (-2) + 4 => 3 * 4 +10 +4 => 12+ 14 = 26.

2006-08-20 17:01:59 · answer #2 · answered by flyfisher_20750 3 · 0 0

The quadratic formulation Ax^2 + Bx + C = 0 solves for x as x = [-B +or- sqrt(B^2 - 4*A*C) ]/ 2*A right here A=3, B= -5, and C = -2 and x = [-(-5) +or- sqrt((-5)^2 - 4*3*(-2)) ]/ 2*3 = [5 +or- sqrt(25 + 24) ] / 6 = [5 +or- sqrt(40 9) ] / 6 = [5 +or- 7 ] / 6 = (5+7)/6 or (5-7)/6 = 12/6 or -2/6 =2 or -a million/3 So x were given values 2 and -a million/3. in case you position those values in the position of x in that equation you would possibly want to comprehend that is authentic.

2016-11-26 20:45:08 · answer #3 · answered by beat 4 · 0 0

3(-2)^2-5(-2)+4=12+10+4=26

2006-08-20 17:54:05 · answer #4 · answered by Anonymous · 0 0

substitute all the x's for -2 so that it reads:
3(-2)^2-5(-2)+4
to solve it you need to specify if 3x is raised to 2 or to 2-5x+4
if the former the answer is:
3(4)+10+4 = 12+10+4 = 26

2006-08-20 16:58:35 · answer #5 · answered by Anonymous · 0 0

26

2006-08-20 16:54:04 · answer #6 · answered by lessthan3ron 2 · 0 0

plug in (-2) everywhere there is an x .... ( this is also the point on the graph of that function)
-2 squared is 4 times 3 is 12
-5 * (-2) = 10 12+10+4 = 26 the point (-2,26) is on the curve of that function's graph

2006-08-20 17:09:43 · answer #7 · answered by Brian D 5 · 0 0

You substitute, 3(-2)^2-5(-2)+4, which by the way equals 26.

2006-08-20 16:55:05 · answer #8 · answered by Anonymous · 0 0

just evaluate at x=-2 and get 26. trivial.

2006-08-20 16:55:14 · answer #9 · answered by d/dx+d/dy+d/dz 6 · 1 0

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