Can anyone supply me with a complex calculus expression that equals 0(zero) and another one that equals 100?

Answer 1

Sure. Why?

2π
∫sin(x) dx = 0
0

10
∫2x dx = 100
0

Answer 2

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Answer 3

How about e^(jπ) +1 = 0 and -100je^(jπ/2) = 100 ?


Doug

Answer 4

The fact that i don't know how to use integral symbols and all that junk on the computer keeps me from goin more complex, but how bout:

lim (x^2-2x-8) = 0
x~>4

lim (20x)/1.8 = 100
x~>9

Answer 5

(1+2+3+...+720) - (6!*(6!+1)/2)=0