The Team plays 36 games this year. At mid-season they won 16 games ...?

Question

The Team plays 36 games this year. At mid-season they won 16 games . How many of the remaining games must they win in order to win at least 80%of all their games. I know the answer is 13 remaining games cause i guessed and checked but i don't know how to set this up?

Answer 1

80% of 36 is 28.8 (meaning 29) subtract 16 they already won then they need to win 13 to reach 29 wins and make 80% of 36

Answer 2

Note: half season is 18 games. Want to win at least 80% (.80) for the season. First half is 16/18. Second half is x /18. Combining yields (16 + x )/36 and this must equal .80 The equation is (16 + x )/36 = .80 => 16 + x = .80 * 36 = 28.8 (round up) 29 => 16 + x = 29 => x = 29 - 16 = 13.

Answer 3

First, the need to find out how many games is 80% of 36 games.

36 X 80 % = 36 X 0.8 = 28.8 games

since you cannot win 0.8 games, you need to round up to 29 games.

Therefore, the game needs to win 29 games in total to win 80% of 36 games. They have already won 16 games.

29 - 16 = 13 games

Answer 4

if the team is required to win 80% of all their games then .80 * 36 = 28.8 or 29 games. since they need to win 29 games and have won 16 the 29 (need to win) -16 (already won) = 13 games to win..

Answer 5

with 18 played and 16 won...your left with the same 18 games...

80% of 36 is 29 games ..... (rounded to obtain AT LEAST)
you've won 16 already ... so

29 you need - 16 you have = 13 more to win

Answer 6

You want this:

16 + X >= 0.80 * 36

X >= 28.8 - 16

X >=12.8

Since you know X has to be an integer that is greater than or equal 12.8, it has to be 13

Answer 7

Pyramider is correct.