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the problem is 18-2y/4>3/2(y+1/3)=3/2-1/2y the answer is 2>y>or =1/2 but I can't figure out how they got the answer to this problem

2006-08-20 13:36:21 · 7 answers · asked by Anonymous in Science & Mathematics Mathematics

7 answers

Unfortunately, the limits of trying to express a formula using ASCII characters are not helping me understand the exact nature of the original equation. You may wish to try it again, using lots of parentheses to indicate clearly the order of operations.

2006-08-20 13:45:06 · answer #1 · answered by Anonymous · 0 0

y +3

2006-08-20 13:42:09 · answer #2 · answered by nooyleinad 2 · 0 1

The problem should be written in the following way:

(18-2y)/4>3/2(y+1/3)>=3/2-1/2y

if (18-2y)/4=a
3/2(y+1/3)=b
3/2-1/2y=c

then you should find all possible meaning of y (the range of y) for which the equation a>b>=c will have sense.

in order to resolve the problem, it should be sepatated in parts:

1. 3/2(y+1/3)>=3/2-1/2y
3/2y+3/2x1/2>=3/2-1/2y
3/2y+1/2>=3/2-1/2y
3/2y+1/2y>=3/2-1/2
4/2y>=2/2
2y>=1
y>=1/2

This was the first part, so we know the lowest possible meaning of y, now the second part:

2. (18-2y)/4>3/2(y+1/3)
9/2-1/2y>3/2y+1/2
9/2-1/2>3/2y+1/2y
8/2>4/2y
4>2y
2>y

so the range of y is [1/2,2) in other expression 2>y>=1/2

2006-08-20 14:25:13 · answer #3 · answered by giviko2 2 · 1 0

Distribute the 3/2 then find the common denominator so that you can wipe out the fractions. Just follow PEMDAS.

2006-08-20 13:47:57 · answer #4 · answered by Anonymous · 0 1

Well, just keep working on it and will come. Let me know once you figured it out.

2006-08-20 13:42:08 · answer #5 · answered by O'Shea 5 · 0 1

Neither can I.

In fact....... I can't see how anybody can get much of anything out of that mess that you've put up there.


Doug

2006-08-20 13:48:14 · answer #6 · answered by doug_donaghue 7 · 0 1

What is Y arent you suppose to be figuring out what Y is. Seriously e mail me with the answer to that please.
Gracie.

2006-08-20 13:42:51 · answer #7 · answered by yourdoneandover 5 · 0 1

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